Answer:
Explanation:
The O-F glucose test (oxidative-fermentation) is used to determine whether an organism is performs oxidative or fermentative metabolism.
Oxidative metabolism (i.e respiration) takes place in the presence of oxygen while fermentative takes place in the absence of oxygen.
Facultative anaerobes can carry out both fermentation and respiration.
The O-F medium has glucose, peptones and a pH indicator. When the pH of the medium is acidic, that is glucose has been broken down, the medium turns yellow. When it is basic, it turns blue implying that peptone and not glucose had been broken down.
The sealed tube is overlaid with oil so as to prevent oxygen from getting in, making it anaerobic.
The unsealed tube allows oxygen.
Enterics would be yellow is both tubes because they are facultative anaerobes and can grow in the presence or absence of oxygen, hence they carry out both respiration and fermentation.
Answer:
The most appropriate answer would be option B.
The flaw in their reasoning is that they compared different molecules in a different set of organisms.
For example, they compared the DNA of lizard A and B whereas they compared the RNA of lizard B and C.
In addition, the mutation rates of different molecules (DNA and RNA) are different and thus, comparison of DNA in one set of organism and comparison of RNA in another set cannot be used as the basis for the conclusion.
Increases is the answer to all of them! I hope this helped and have a great day
This membrane is called a selectively permeable membrane as it only allows for the entry of specific substances and does not allow of others.
They are just wrestling don’t worry
