Saturday, nola bowled 3 games in her bowling league. she had a mean score of 115. the score of her first game was 110. the score
2 answers:
Answer: A.145
Step-by-step explanation:
Given : Nola bowled 3 games in her bowling league.
She had a mean score of 115.
The score of her first game was 110.
The score of her second game was 90.
Let x denotes the score of her third game.
The formula to find the mean score is given by :-
Multiply 3 on both the sides, we get
Subtract 200 from both the sides , we get
Therefore. the score of her third game = 145
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The solution to this system of inequalities x + y>4 , x + y <3 is Option A
The complete question is
Which graph shows the solution to this system of inequalities? x + y>4 x + y <3
The image are attached with the answer.
<h3>What are Inequality ?</h3>When an expression is equated with another expression by an Inequality operator (< , > < etc) then the mathematical statement formed is called Inequality.
The inequalities are
x+y>4
x + y <3
After plotting both the inequalities in the graph the following graph that is attached with the answer is obtained.
Therefore the correct answer is Option A
To know more about Inequalities
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Answer:
The students should request an examination with 5 examiners.
Step-by-step explanation:
Let <em>X</em> denote the event that the student has an “on” day, and let <em>Y</em> denote the
denote the event that he passes the examination. Then,
The events () follows a Binomial distribution with probability of success 0.80 and the events (
) follows a Binomial distribution with probability of success 0.40.
It is provided that the student believes that he is twice as likely to have an off day as he is to have an on day. Then,
Then,
⇒
Then,
Compute the probability that the students passes if request an examination with 3 examiners as follows:
The probability that the students passes if request an examination with 3 examiners is 0.715.
Compute the probability that the students passes if request an examination with 5 examiners as follows:
The probability that the students passes if request an examination with 5 examiners is 0.734.
As the probability of passing is more in case of 5 examiners, the students should request an examination with 5 examiners.