Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
Answer: Use the distributive property to multiply 3 by y−4.
3y−12−2(y−4)
Use the distributive property to multiply −2 by y−4.
3y−12−2y+8
Combine 3y and −2y to get y.
y−12+8
Add −12 and 8 to get −4.
Anwser:
y−4
Step-by-step explanation:
Hope this helps!
Answer: 0.5
1) convert to I proper fraction
2) divide the fraction
