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polet [3.4K]
4 years ago
15

Combine like terms y+6+5(y+8)

Mathematics
1 answer:
Irina18 [472]4 years ago
4 0
Y + 6 + 5(y+8)
perform distributive property of multiplication
y + 6 + 5y + 40
y + 5y + 6 + 40
6x + 46

Like terms are terms that have the same variables and powers. Coefficient of these terms do not need to match. 
 
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Given square JKLM and t(-6,4) t (1,5) ​(JKLM)​RSTU, what is the area of​ RSTU?
Dafna1 [17]

Answer:

  • 144 cm²

Step-by-step explanation:

<u>The given translation doesn't change the shape or dimensions, hence the area remains same:</u>

  • A = a² = (12 cm)² = 144 cm²
5 0
2 years ago
Read 2 more answers
Solve. <br> 1/2x - 2/5x = -2
Makovka662 [10]
1/2x - 2/5x = -2

1/10x = -2

x = -20
3 0
3 years ago
HELP ME PLZZZ!!!! URGENT!!!​
finlep [7]

Answer:

Step-by-step explanation:

Given equation is,

x² + (p + 1)x = 5 - 2p

x² + (p + 1)x - (5 - 2p) = 0

x² + (p + 1)x + (2p - 5) = 0

Properties for the roots of a quadratic equation,

1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]

2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]

3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].

Discriminant of the given equation = (p+1)^2-4(1)(2p-5)

For real roots,

(p+1)^2-4(1)(2p-5)>0

p² + 2p + 1 - 8p + 20 > 0

p² - 6p + 21 > 0

For all real values of 'p', given equation will be greater than zero.

5 0
3 years ago
5^5=75+30<br><br> TRUE OR FALSE<br><br><br> p.s. if this gets deleted ama demolish u
agasfer [191]

false is the answer.

7 0
3 years ago
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The sum of the ages of Berma, her mother Rinna and her father Erwin is 80. Two years from now, Rinna’s age will be 13 less than
jekas [21]

Answer: Berma is 5 years old

Rinna is 38 years old

Erwin is 37 years old

Step-by-step explanation:

Let x represent Berma's age

Let y represent Rinna's age

Let z represent Erwin's age

Since the sum of their ages is 80,

x + y + z = 80 - - - - - - -1

Two years from now, Rinna’s age will be 13 less than the sum of Erwin’s age and twice Berma’s age. This means that

y +2 = [ (z+2) + 2(x+2) ] - 13

y +2 = z + 2 + 2x + 4 - 13

2x - y + z = 13 + 2 - 4 -2

2x - y + z = 9 - - - - - - -2

Three years ago, 15 times Berma’s age was 5 less than the age of Rinna. It means that

15(x - 3) = (y - 3) - 5

15x - 45 = y - 3 - 5

15x - y = - 8 + 45

15x - y = 37 - - - - - - - -3

From equation 3, y = 15x - 37

Substituting y = 15x - 37 into equation 1 and equation 2, it becomes

x + 15x - 37 + z = 80

16x + z = 80 + 37 = 117 - - - - - - 4

2x - 15x + 37 + z = 9

-13x + 2 = -28 - - - - - - - - -5

subtracting equation 5 from equation 4,

29x = 145

x = 145/29 = 5

y = 15x - 37

y = 15×5 -37

y = 38

Substituting x= 5 and y = 38 into equation 1, it becomes

5 + 38 + z = 80

z = 80 - 43

z = 37

6 0
3 years ago
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