3 years ago

Can anyone help me find the answer to this question?

1 answer:

galina1969 [7]3 years ago

3 0

Find a 92.9% confidence interval for the difference p1−p2p1−p2 of the population proportions.

Hint: For a level of confidence (1−α)⋅100%(1−α)⋅100%, z∗z∗ is the value that leaves an area of (1−α)/2(1−α)/2 to its right in a standard normal distribution

I hope that helps

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