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2 years ago

Which expression has a value of 18 when n=7?

Mathematics

2 answers:

Lorico [155]2 years ago

8 0

Hello There!

I'm sure it is B. 6n - 24

Hope This Helps You!
Good Luck :)

- Hannah ❤

snow_lady [41]2 years ago

6 0

Check all the options by plugging n = 7

50 - 3(7) = 50 - 21 = 29 (not possible)

6(7) - 24 = 42 - 24 = 18 (possible)

So correct option is B

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Please Show Work.

s344n2d4d5 [400]

Answer:

$\huge\boxed{x=17}$

Step-by-step explanation:

It's important to note that when two angles create a straight line, they are supplementary.

This means their angle measures add up to 180° since a 180° angle is a straight line.

Since we know the measures of both angles in equation form, we can add them together and have them equal 180 to solve for x.

$(5x-18) + (4x+45) = 180$

Combine like terms:

$9x + 27 = 180$

Subtract 27 from both sides:

$9x = 153$

Divide both sides by 9:

$x = 17$

So x = 17.

Hope this helped!

5 0

3 years ago

Read 2 more answers

It says to use compatible numbers also help!

Rus_ich [418]

First, multiply 30 with 25

30 x 25 = Area

Area = 750 square yards

one bag gives you 100 square yards

Divide the two numbers

750/100 = 7.5

Since you cannot buy half a bag, you must round up

8 bags is needed

hope this helps

4 0

3 years ago

Read 2 more answers

What is the area of this figure 3,7,7

IRINA_888 [86]

I think the answer is 147

4 0

2 years ago

Differentiate the function. y = (3x - 1)^5(4-x^4)^5

TiliK225 [7]

Answer:

$\displaystyle y' = -5(3x-1)^4(4 - x^4)^4(15x^4 - 4x^3 - 12)$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Algebra I

Terms/Coefficients
Factoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

y = (3x - 1)⁵(4 - x⁴)⁵

Step 2: Differentiate

Product Rule: $\displaystyle y' = \frac{d}{dx}[(3x - 1)^5](4 - x^4)^5 + (3x - 1)^5\frac{d}{dx}[(4 - x^4)^5]$
Chain Rule [Basic Power Rule]: $\displaystyle y' =[5(3x - 1)^{5-1} \cdot \frac{d}{dx}[3x - 1]](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^{5-1} \cdot \frac{d}{dx}[(4 - x^4)]]$
Simplify: $\displaystyle y' =[5(3x - 1)^4 \cdot \frac{d}{dx}[3x - 1]](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^4 \cdot \frac{d}{dx}[(4 - x^4)]]$
Basic Power Rule: $\displaystyle y' =[5(3x - 1)^4 \cdot 3x^{1 - 1}](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^4 \cdot -4x^{4-1}]$
Simplify: $\displaystyle y' =[5(3x - 1)^4 \cdot 3](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^4 \cdot -4x^3]$
Multiply: $\displaystyle y' = 15(3x - 1)^4(4 - x^4)^5 - 20x^3(3x - 1)^5(4 - x^4)^4$
Factor: $\displaystyle y' = 5(3x-1)^4(4 - x^4)^4\bigg[ 3(4 - x^4) - 4x^3(3x - 1) \bigg]$
[Distributive Property] Distribute 3: $\displaystyle y' = 5(3x-1)^4(4 - x^4)^4\bigg[ 12 - 3x^4 - 4x^3(3x - 1) \bigg]$
[Distributive Property] Distribute -4x³: $\displaystyle y' = 5(3x-1)^4(4 - x^4)^4\bigg[ 12 - 3x^4 - 12x^4 + 4x^3 \bigg]$
[Brackets] Combine like terms: $\displaystyle y' = 5(3x-1)^4(4 - x^4)^4(-15x^4 + 4x^3 + 12)$
Factor: $\displaystyle y' = -5(3x-1)^4(4 - x^4)^4(15x^4 - 4x^3 - 12)$