Considering the given stem-and-leaf plot, the quartiles are given as follows:
- The first quartile is of 67.5.
- The second quartile, which is the median, is of 84.5.
- The third quartile is of 91.5.
<h3>What are the median and the quartiles of a data-set?</h3>
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
There is an even number of elements(26), hence the median is the mean of the 13th and 14th elements, which are 83 and 86, hence:
Me = (83 + 86)/2 = 84.5.
The first half has 12 elements, hence the first quartile is the mean of the 6th and 7th elements, which are 67 and 68, hence:
Q1 = (67 + 68)/2 = 67.5.
The third half also has 12 elements, starting at the second 86, hence the third quartile is the mean of the 6th and 7th elements of this half, hence:
Q3 = (91 + 92)/2 = 91.5.
More can be learned about the quartiles of a data-set at brainly.com/question/28017610
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Answer:
82.35%
Step-by-step explanation:
60 divided by 340=0.17647058823
Multiply that by 100 and you get 17.647058823
Next, round and you get 17.65
100-17.65=82.35
Answer:
0.9855 or 98.55%.
Step-by-step explanation:
The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:
The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.
Answer:4 hours
Step-by-step explanation:
6*2=12
12/3=4
