We are given 3 equations. Using these equations we can find f(h(2)).
h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9
f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74
so f(h(2))=74
Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
The answer is D. The bus picked up people, and the graph is saying it dropped people off.
Answer:
x=510
Step-by-step explanation:
You can first combine like terms to get x/17=30
The inverse operation of division is multiplication so you can multiply by 17 on both sides to get your final answer: x=510
- Line<span> of </span>Best Fit<span>. A </span>line<span> of </span>best fit<span> (or "</span>trend<span>" </span>line<span>) is a straight </span>line<span> that </span>best<span> represents the data on a </span>scatter plot<span>. This </span>line<span> may pass through some of the points, none of the points, or all of the points.</span>
