Answer:
3137 + 3791
Step-by-step explanation:
you add all 3 first, lets try with the first one
3137 + 3791= 6928
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
C is your answer e cause u supposed to multiple
72's factors is doubled the factors of 36.
Let the number of seats of the smaller van be "x". Since it travels two times in the morning, it will be 2x. The bigger van has 14 more seats than the small one, so it will be x + 14. To find the value of x, the formula would be,
65 = 2x + x + 14
65 = 3x + 14
65 - 14 = 3x
51 = 3x
51/3 = x
17 = x
The value of x is 17.
Van A = 17 seats + 14 seats = 31 seats
Van B = 2 (17 seats) = 34 seats
Van A has 31 seats for 31 people for a single trip.
Van B has 17 seats, and since it has two trips, it can transport 34 people.