Measure of the angle m ∠ RQS = 58 ° for the given circle with arc RS subtending m ∠RPS=14 x + 46 ° at the center P and m ∠ RQS = 3 x + 43 ° at Q, on the circumference.
As given in the question,
Measure of the angle is given by :
m ∠ RPS=14 x + 46 °
m ∠ RQS=3 x + 43 °
m ∠ RPS = twice m ∠RQS (angle subtended at center of the circle)
14 x +46 =2(3 x + 43)
⇒ 14x + 46 = 6x +86
⇒ 14x-6x=86-46
⇒8x=40
⇒ x=5°
m ∠ RQS = (3 x + 43) °
=[3(5) + 43 ]°
= 58°
Therefore, measure of the angle in the given circle m ∠RQS is equal to the 58 °
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first we need to get rid of the ( ) so that we can see what the question really says
(3x³-5x² - 7+ 4x4) + (9x4 - 10x² - 5x³ + 3)
= 3x³-5x²-7+4x⁴+9x⁴-10x²-5x³+3
now all we need to do is add up the numbers with the same x's
<em>3x³</em>-5x²-7<u>+4x⁴+9x⁴</u>-10x²<em>-5x³</em>+3
= 13x⁴-2x³-15x²-4
Answer: x=19
Step-by-step explanation:
x=31-12
x=19
Y=Mx+C
-8=m(-3)+(-5)
-8=-3m-5
-8+5= -3m
-3= -3m
— —
-3 -3
0=m
M=o
Therefore the equation is y=0x+ (-5)
