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Alona [7]
4 years ago
5

What is DBMS software used for?

Computers and Technology
1 answer:
Alexandra [31]4 years ago
5 0
A database management system<span> (DBMS) is system software for creating and managing databases. The DBMS provides users and programmers with a systematic way to create, retrieve, update and manage data.</span>
You might be interested in
How have productivity programs improved the professional lives of people? (check all that apply)
Zielflug [23.3K]

Productivity programs improved the professional lives of people because:

  • made it easier and faster to communicate with others
  • made it easier to manipulate numbers in a spreadsheet
  • made it easier and less expensive to present information

<h3>What is productivity?</h3>

Productivity is known to be the level of efficiency in regards to the production of goods or services and it is one that is rated by some measure.

Hence, Productivity programs improved the professional lives of people because:

  • made it easier and faster to communicate with others
  • made it easier to manipulate numbers in a spreadsheet
  • made it easier and less expensive to present information

Learn more about productivity from

brainly.com/question/14262252

#SPJ1

7 0
2 years ago
Define a method calcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a d
enyata [817]

Answer:

The method in C++ is as follows:

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

   double baseArea = calcBaseArea(baseLength, baseWidth);

   double volume = baseArea * pyramidHeight;

   return volume;    

}

Explanation:

This defines the calcPyramidVolume method

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

This calls the calcBaseArea method to calculate the base area of the pyramid

   double baseArea = calcBaseArea(baseLength, baseWidth);

This calculates the volume

   double volume = baseArea * pyramidHeight;

This returns the volume

   return volume;  

}

<em>See attachment for complete program that include all methods that is required for the program to function.</em>

5 0
3 years ago
Which is true about TCP and UDP? Choose two answers.
vichka [17]

Answer:

TCP is a connection-oriented protocol

UDP does not acknowledge a receipt of data

Explanation:

TCP (Transmission Control Protocol) is a protocol to transfer data, this is one of the most important protocols on the entire internet, this method was implemented from the beginning of the network.

UDP (User Datagram Protocol) this is a protocol faster than TCP because this method doesn't establish a connection to sent data, in this case, always sent data, but TCP is more secure than UDP, and for that UDP is used to transfer music or videos, and TCP websites and database.

UDP doesn't need acknowledgment is done by UDP, is only concerned with speed.

7 0
4 years ago
File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
myrzilka [38]

Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

       amount = input.nextInt();

       for (int i=0; i<sales.length; i++)

    {

     if(sales[i] > amount) {

         counter++;

         System.out.println("Salesperson "+ (i+1) + " exceeded given amount. (Number of sales: " + sales[i] +")");

     }

    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

8 0
3 years ago
Convert the following four unsigned binary numbers to decimal and show your work:
Ber [7]

Answer:

23 ,21,10,63,13

Explanation:

We have to convert binary to decimal

10111 corresponding decimal number is

1\times 2^4+0\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=23

10101 corresponding decimal number is

1\times 2^4+0\times 2^3+1\times 2^2+0\times 2^1+1\times 2^0==21

01010 corresponding decimal number is

0\times 2^4+1\times 2^3+0\times 2^2+1\times 2^1+0\times 2^0=10

111111 corresponding decimal number is

1\times 2^5+1\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=63

001111 corresponding decimal number is

0\times 2^5+0\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=13

7 0
4 years ago
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