Whenever a problem says "one number" and "another number" we can substitute x and y. for this we have x=2y+1 and xy=1. since we know the value of x (2y+1) we can substitute it for the other equation to get (2y+1)y=10. simplify to get 2y^2+y=10. from here you can do a few methods to solve this, but the simplest in my opinion is by factoring.

In order to factor it must be equal to 0, so we have 2y^2+y-10=0. We factor this and get y=5 (we also get y=-4 but it is an extraneous root). now we can plug that into either equation and find that x=2.

this means our two numbers are 5 and 2

3 0

3 years ago

ving as a relation, state the domain and range, then determine if it is a6.2X-2 0.-2Relation:DomainRangeFunction3 i

Travka [436]

The relation is the set of ordered pairs of point drawn in the graph

The points are:

(-2, 3), (0, 1), (2, -1), (3, -2)

So the relation is:

R = {(-2, 3), (0, 1), (2, -1), (3, -2)}

The domain is the values of x in the ordered pairs

x = -2, 0, 2, 3

The domain = {-2, 0, 2, 3}

The range is the values of y in the ordered pairs

y = 3, 1, -1, -2

Arrange them in the set

The range = {-2, -1, 1, 3}

7 0

1 year ago

A pair of shoes is on sale for 80% off the original price. The sale price is $60. What was the original price

ella [17]

I am not sure but it might be $12

6 0

3 years ago