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anygoal [31]
3 years ago
11

Creatinine, , is a by-product of muscle metabolism, and creatinine levels in the body are known to be a fairly reliable indicato

r of kidney function. The normal level of creatinine in the blood for adults is approximately 1.0 mg per deciliter (dl) of blood. If the density of blood is 1.025 g/ml, calculate the molality of a normal creatinine level in a 10.0-ml blood sample.
Chemistry
1 answer:
kherson [118]3 years ago
7 0

Answer:

Molality = 0.0862 mole/kg

Explanation:

Molality = (number of moles of solute)/(mass of solvent in kg)

Number of moles of solute = (mass of Creatinine in the blood sample)/(Molar mass of Creatinine)

To obtain the mass of creatinine in 10 mL of blood. We're told that 1 mg of Creatinine is contained in 1 decilitre of blood.

1 decilitre = 100 mL

1 mg of Creatinine is contained in 100 mL of blood

x mg of Creatinine is contained in 10 mL of blood.

x = (1×10/100) = 0.1 mg = 0.0001 g

Molar mass of Creatinine (C₄H₇N₃O) = 113.12 g/mol

Number of moles of Creatinine in the 10 mL blood sample = (0.0001/113.12) = 0.000000884 moles

Mass of 10 mL of blood = density × volume = 1.025 × 10 = 10.25 mg = 0.01025 g = 0.00001025 kg

Molality of normal creatinine level in a 10.0-ml blood sample = (0.000000884/0.00001025)

Molality = 0.0862 moles of Creatinine per kg of blood.

Hope this Helps!!!

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Answer:

Viscosity

Explanation:

The viscosity of the liquid is the independent variable. The flow rate is the dependent variable in this hypothesis.

The statement given is called the hypothesis. It is a form of scientific guess into a phenomenon.

  • An independent variable is the cause.
  • A dependent variable is the effect produced.
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3 0
3 years ago
The atomic mass of Cu is 63.5. Find its electrochemical equivalent​
FrozenT [24]

Answer:

The electrochemical equivalent of copper, Cu, is 3.29015544 × 10⁻⁷ g/C

Explanation:

The given parameters are;

The element for which the electrochemical equivalent is sought = Copper

The atomic mass of copper = 63.5

The electrochemical equivalent, 'Z', of an element or a substance is the mass, 'm', of the element or substance deposited by one coulomb of electricity, which is equivalent to a 1 ampere current flowing for a period of 1 second

Mathematically, we have;

m = Z·I·t = Z·Q

We have;

Cu²⁺ (aq) + 2·e⁻ → Cu

Therefore, one mole of Cu, is deposited by 2 moles of electrons

The charge carried one mole of electrons = 1 Faraday = 96500 C

∴ The charge carried two moles of electrons, Q = 2 × 96500 C = 193,000 C

Given that the mass of an atom of Cu = 63.5 a.m.u., the mass of one mole of Cu, m = 63.5 g

Z = \dfrac{m}{Q} = \dfrac{63.5 \ g}{193,000 \ C} = 3.29015544 \times 10^{-4} \, g \cdot C^{-1}

∴ Z = 3.29015544 × 10⁻⁴ g/C = 3.29015544 × 10⁻⁷ g/C

The electrochemical equivalent of copper, Cu, is Z = 3.29015544 × 10⁻⁷ g/C

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Explanation:

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xxTIMURxx [149]

Answer:

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