A solution with a Ph of 2 has a H+ ion concentration that is two times greater than a solution with a ph of 4. The Ph of 2 and 4 indicate that the solution is acidic since they are less than PH of 7. The H+ ions are more present when the solution is acidic but the Ph differ with concentration H+ ions. The solution with a Ph of 2 has more H+ than the solution with Ph of 4 thus the solution with Ph of 2 has more hydrogen ions than that of 4
It’s 8 electrons. “octa” means 8
When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M
The reaction of neutralization of HNO₃ with NaOH is
HNO₃ + NaOH → H₂O + NaNo₃
When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -
With the mole and volumes, we can find molarity as follows:
Moles of NaOH = moles HNO₃
⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH
=0.014 mol HNO₃
Molarity: -

= 0.041 M
Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.
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Answer:
True: Sodium Chloride Solution will conduct Electricity.
Explanation:
When Sodium Chloride is in solid form it fails to conduct current, But when it is dissolved in water it dissociates to produce a Na⁺ and Cl⁻ ions which are current conducting between two electrodes.
NaCl ₍s₎ + H₂O → Na⁺ ₍aq₎ + Cl⁻₍aq₎
The corect answers will be:
1) A
2) B
3) D
Hope this helped :)