The gravitational pull of the Sun affects which of the following properties of the planets in our solar system?

Find the pH of a 0.100 molar H2C6O6 solution with ka, where KA is equal 8.0×10–5

lubasha [3.4K]

The pH of the solution is 2.54.

Explanation:

pH is the measure of acidity of the solution and Ka is the dissociation constant. Dissociation constant is the measure of concentration of hydrogen ion donated to the solution.

The solution of C₆H₂O₆ will get dissociated as C₆HO₆ and H+ ions. So the molar concentration of 0.1 M is present at the initial stage. Lets consider that the concentration of hydrogen ion released as x and the same amount of the base ion will also be released.

So the dissociation constant Kₐ can be written as the ratio of concentration of products to the concentration of reactants. As the concentration of reactants is given as 0.1 M and the concentration of products is considered as x for both hydrogen and base ion. Then the

$K_{a}=\frac{[H^{+}][HB] }{[reactant]}$

[HB] is the concentration of base.

$8 * 10^{-5} =\frac{x^{2} }{0.1}\\\\\\x^{2} = 8 * 10^{-5}*0.1$

$x^{2} = 0.08 * 10^{-4}\\ \\x = 0.283*10^{-2}$

Then

$pH = - log [x] = - log [ 0.283 * 10^{-2}]\\ \\pH = 2 + 0.548 = 2.54$

So the pH of the solution is 2.54.

4 0

3 years ago

Add them to your friend's list and have them support you along your Brainly journey. Just go to the profile of the person you’d

Makovka662 [10]

Answer:

yup that's how you make friends with people on brainly

8 0

2 years ago

Which of these formulas is NOT consistent with the guidelines for creating ionic compounds? Mark all that apply.

iVinArrow [24]

Answer:

d

Explanation:

because boron and fluorine are both nonmetals and don't fit the guidlelines for creating ionic compounds

8 0

3 years ago

If I have 12 protons, how many neutrons and electrons would I need to make a stable atom?

lesantik [10]

Answer:

im pretty sure you need 15 in all but dont get mad it thats wrong, so you would i think need 3 neutrons

Explanation:

3 0

3 years ago

Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)

Stels [109]

<span> Au</span>₂(SeO₄)₃

O = -2 × 4 = -8
Se = + 6
So,
(+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3

-2 ₓ 3 = -6
Means,
Au₂ + (-6) = 0

Au₂ = +6
Or,
Au = 6 / 2

Au = +3
Result:
Au = +3
Se = +6
O = -2

Ni(CN)₂

Cyanide (CN⁻) contains -1 charge,
So,
N = -3
C = +2
Then,
Ni + (-1)₂ = 0

Ni - 2 = 0
Or,
Ni = +2
Result:
N = -3
C = +2
Ni = +2

6 0

3 years ago