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3 years ago

9.51 as a mixed number in a simplest form

Mathematics

2 answers:

Triss [41]3 years ago

7 0

Answer:

Below

Step-by-step explanation:

9 $\frac{51}{100}$

ehidna [41]3 years ago

6 0

Answer: 9 51/100

Step-by-step explanation:

STEP 1. Convert it into improper fraction

9.51=951/100

STEP 2. Convert improper fraction into mixed fraction

951 ÷ 100=9 R 51

9 51/100

Hope this helps!! :)

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Shkiper50 [21]

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Elenna [48]

Answer:

Step-by-step explanation:

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3 years ago

Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini

Nat2105 [25]

By inspection, it's clear that the sequence must converge to $\dfrac32$ because

$\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32$

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Now, for the limit as $n\to\infty$ to be equal to $\dfrac32$ is to say that for any $\varepsilon>0$ , there exists some $N$ such that whenever $n>N$ , it follows that

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|$

From this inequality, we get

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}$
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$\implies n\dfrac12+\dfrac5{4\varepsilon}$

As we're considering $n\to\infty$ , we can omit the first inequality.

We can then see that choosing $N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil$ will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that $N\in\mathbb N$ .

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3 years ago

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Ulleksa [173]

Answer:

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8x = 1

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3 years ago

How many pairs of whole numbers have a sum of 40

Alex

For the writer, there are 20
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2. 2 + 38 = 40
3. 3 + 37 = 40
4. 4 + 36 = 40 
5. 5 + 35 = 40 
6. 6 + 34 = 40
7. 7 + 33 = 40
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9. 9 + 31 = 40
10. 10 + 30 = 40 
11. 11 + 29 = 40 
12. 12 + 28 = 40
13. 13 + 27 = 40 
14. 14 + 26 = 40 
15. 15 + 25 = 40 
16. 16 + 24 = 40 
17. 17 + 23 = 40 
18. 18 + 22 = 40 
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3 years ago