Answer:
The exact answer in terms of radicals is ![x = 5*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%205%2A%5Csqrt%5B3%5D%7B25%7D)
The approximate answer is 
(accurate to 5 decimal places)
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Work Shown:
Let ![y = \sqrt[5]{x^3}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B5%5D%7Bx%5E3%7D)
So the equation reduces to -7 = 8-3y
Let's solve for y
-7 = 8-3y
8-3y = -7
-3y = -7-8 ... subtract 8 from both sides
-3y = -15
y = -15/(-3) ... divide both sides by -3
y = 5
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Since and y = 5, this means we can equate the two expressions and solve for x
![\sqrt[5]{x^3} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%20%3D%205)
Raise both sides to the 5th power
![x = \sqrt[3]{3125}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B3125%7D)
Apply cube root to both sides
![x = \sqrt[3]{125*25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%2A25%7D)
![x = \sqrt[3]{125}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B25%7D)
![x = \sqrt[3]{5^3}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B5%5E3%7D%2A%5Csqrt%5B3%5D%7B25%7D)
Answer:
y= 1 and x=-2
Step-by-step explanation:
Since they both equal y, you can equal them to each other:
x + 3 = 2x + 5
Then solve:
x - x + 3 = 2x - x + 5
3 - 5 = x + 5 - 5
-2 = x
Substitute x in either equation to solve for y:
y = (-2) +3
y = 1
Or the other equation:
y = 2(-2) + 5
y = -4 + 5
y = 1
hope this helps :)
Answer: x=6
Step-by-step explanation:
Answer:
B.
Step-by-step explanation:
Trust me.
I just did it.
Answer:
0.3(8.2 x 10^-3) = 2.46 X 10 ^ -3
Step-by-step explanation:
We need to solve the equation 0.3(8.2 x 10^-3) and write answer in scientific notation.
Solving,
= 0.3(8.2 x 10^-3)
= 0.3 * 0.0082
= 0.00246
Writing in scientific notation
= 2.46 X 10 ^ -3
So, after solving the expression 0.3(8.2 x 10^-3) the result is 2.46 X 10 ^ -3.
