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4 years ago

Plz help ill give u brainlist

Mathematics

2 answers:

Alex4 years ago

7 0

The diameter is 2r -- two times the radius.
Radius = 11
Diameter = 5x + 7

Plug the radius and diameter into the equation D = 2r.
5x + 7 = 2(11)

5x + 7 = 22
5x = 15
x = 3

The answer is C) 5x + 7 = 22.
The value of x is 3.

belka [17]4 years ago

6 0

C. 5x+7=22 since diameter is equal to double the radius. radius=11 so diameter equals 22. then just make 5x+7 = to 22

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Answer:

Answer is A.

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3 years ago

Find the geometric mean of 8 and 253.

sveta [45]

The geometric mean of 8 and 253 is;

<h3>Geometric mean of numbers</h3>

According to the question;

The task requires that the geometric mean of 8 and 253 be determined.

The geometric mean of a two numbers is the square root the product of the he numbers.

Hence, in this scenario;

The geometric mean of 8 and 253 is;

G.M = √8×253

G.M = √2024

G.M = 45.

Ultimately, the geometric mean of 8 and 253 is approximately 45.

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Is 49.20 greater than 49.22

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3 years ago

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Yuliya22 [10]

Answer:

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Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

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3 years ago

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Step-by-step explanation:

A number that is negative is less than 0, so

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2 years ago

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