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k0ka [10]
4 years ago
15

Plz help ill give u brainlist

Mathematics
2 answers:
Alex4 years ago
7 0
The diameter is 2r -- two times the radius.
Radius = 11
Diameter = 5x + 7

Plug the radius and diameter into the equation D = 2r.
5x + 7 = 2(11) 

5x + 7 = 22
5x = 15
x = 3

The answer is C) 5x + 7 = 22.
The value of x is 3.
belka [17]4 years ago
6 0
C. 5x+7=22 since diameter is equal to double the radius. radius=11 so diameter equals 22. then just make 5x+7 = to 22
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The distance a car travels is directly related to the time it travels. The distance is 300 miles when time is 5 hours. What is t
Tema [17]
D = t multiplied by constant of variation so. constant of variation= d / t

constant of variation = 300 / 5 which is equal to 60
4 0
3 years ago
Yolanda finished 3/4of 10 1/2mile race how many mile sdid she complete
Mila [183]

Answer:

She completed 7.5 3/8 miles of the race.

Step-by-step explanation:

This can be solved with multiplication.

10 * 3/4 = 7.5

1/2 * 3/4 = 1 * 3/2 * 4 = 3/8

7 0
3 years ago
The least common multiple of 5 and p is 30 .Which number does p represent?
Colt1911 [192]
I believe it would be 6
3 0
3 years ago
Read 2 more answers
Can some on help me please??
erma4kov [3.2K]

Answer:

Frequency is 2, 2 and 3.

Step-by-step explanation:

Temp in 101 to 106 - In this range only 2 temperature is there 104 and 104 in 2 cities. so frequency is 2.

Temp in 107 to 112 - In this range only 2 temperature is there 107 and 112 in 2 cities. so frequency is 2.

Temp in 113 to 118 - In this range only 3 temperature is there 114, 117 and 118 so frequency is 3.

5 0
3 years ago
Read 2 more answers
What interest rate per annum is a fund paying its clients if the third to the last payment of a depositor became Php 1,040.40 fr
Ainat [17]

Answer: The rate of interest per annum is 1.3%.


Step-by-step explanation:

Given  Principal P= $1000

time period n=3

Amount A=$1040,40

To find rate of interest per annum r

We know that

A=P(1+\frac{r}{100} )^3\\\Rightarrow\ 1040=1000(1+\frac{r}{100})^3\\\Rightarrow\ 1.040=(1+\frac{r}{100})^3\\\text{taking log on both sides}\\log(1.040)=3log(1+\frac{r}{100})\\\Rightarrow0.039=3log(1+\frac{r}{100})\\\Rightarrow0.013=log(1+\frac{r}{100})\\\\\Rightarrow\ e^{0.013}=(1+\frac{r}{100})\\\Rightarrow\ 1.013=(1+\frac{r}{100})\\\Rightarrow\ \frac{r}{100}=1.013-1=0.013\\

⇒  r = 1.3%.

3 0
3 years ago
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