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2 years ago

13

The equations are given below.

1 answer:

amid [387]2 years ago

5 0

Answer:

neither

Step-by-step explanation:

they are parallel when they have the same slope and perpendicular when the slope is completely different

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In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev

Paha777 [63]

Answer:

0.3114

Option d is right

Step-by-step explanation:

Let X be the time spent on a treadmill in the health club

Given that research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes

Also given that X is normal

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

$= P(30$

round off to two decimals tog et

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill is 0.31

Hence option d is right

3 0

3 years ago

I need ASAP please help me

Colt1911 [192]

Answer:

5006 is and 4896

Step-by-step explanation:

math is the best letsgoooo

5 0

1 year ago

elena-s [515]

Answer:

12 in

Step-by-step explanation:

the scale factor of the enlarged frame is found by comparing the widths

original width : enlarged width = 2 : 6 = 1 : 3

That is 3 times the original width , then

enlarged height = 4 × 3 = 12 in

7 0

2 years ago

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago

If ad=30 and dc=30 what is the length of bd

DerKrebs [107]

BD =√30 +√30

BD = 2√30

Here you go

7 0

1 year ago