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3 years ago

A generator stores electric current. Explain why you agree or disagree with this statement

1 answer:

7 0

I disagree, a generator generates electricity so by it's namesake it can't store it, to be used for later. However, the energy being made can be used for a job or task, but it will lose the extra energy it creates.

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Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an

Morgarella [4.7K]

Answer:

2.218 m/s; 4.4375 m/s; 0.01981 m/s²

Explanation:

for more details see the attached picture.

4 0

3 years ago

A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.16

ycow [4]

We assign the variables: T as tension and x the angle of the string
The centripetal acceleration is expressed as v²/r=4.87²/0.9 and (0.163x4.87²)/0.9 = T+0.163gcosx, giving T=(0.163x4.87²)/0.9 – 0.163x9.8cosx.

(1)At the bottom of the circle x=π and T=(0.163x4.87²)/0.9 – .163*9.8cosπ=5.893N. 
(2)Here x=π/2 and T=(0.163x4.87²)/0.9 – 0.163x9.8cosπ/2=4.295N. 
(3)Here x=0 and T=(0.163x4.87²)/0.9 – 0.163x9.8cos0=2.698N. 
(4)We have T=(0.163v²)/0.9 – 0.163x9.8cosx.

This minimum v is obtained when T=0 and v verifies (0.163xv²)/0.9 – 0.163x9.8=0, resulting to v=2.970 m/s.

4 0

3 years ago

Read 2 more answers

How is an appliance's power related to the amount of energy it uses?

zysi [14]

The more powerful an appliance is, the more amounts of energy it uses. For instance a jack hammer that does not create a lot of destruction or change does not use a lot of energy. If a jack hammer that creates a lot of destruction and change probably uses a lot more energy and makes more sound.

6 0

3 years ago

A truck drives with a constant linear speed v_iv i v, start subscript, i, end subscript down a road with two curves. The first

Alex

Answer:

Explanation:

Centripetal acceleration is given by

$a = \dfrac{v^2}{r}$

where v is the linear velocity and r is the radius of the curve.

Let the centripetal acceleration on the curve of radius R be $a_1$ .

Then

$a_1 = \dfrac{v_i^2}{R}$

Let the centripetal acceleration on the curve of radius 3R be $a_2$ .

Then

$a_2 = \dfrac{v_i^2}{3R} = \dfrac{1}{3}\dfrac{v_i^2}{R} = \dfrac{1}{3}a_1$

Here, we see that the acceleration decreases by a factor of 3.

7 0

3 years ago

An automobile travels on a straight road for 40 km at 30 km/h. It then continues in the same direction for another 40 km at 60 k

Butoxors [25]

Answer:

The average velocity is 40km/h.

Explanation:

The average velocity is $\bar{v}=\frac{\Delta x }{\Delta t}$ , where $\Delta x$ is the distance traveled and $\Delta t$ the time elapsed.

The distance traveled is clearly 80km since it's all done in the same direction, we only need to know the time elapsed. For this we calculate the time elapsed on the first part, and add it to the time elapsed on the second part using always the formula $\Delta t=\frac{\Delta x }{v}$ , where v is the velocity on each part, which is constant.

The time elapsed for the first part is $\Delta t_1=\frac{40 km}{30km/h}=\frac{4}{3}h$ , and the time elapsed for the second part is $\Delta t_2=\frac{40 km}{60km/h}=\frac{2}{3}h$ , giving us a total time of $\Delta t_1+\Delta t_2=\frac{4}{3}h+\frac{2}{3}h$ =2h.

Finally, we can calculate the average velocity: $\bar{v}=\frac{80km}{2h}=40km/h$ .

6 0

3 years ago