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sergij07 [2.7K]
3 years ago
5

A truck drives with a constant linear speed v_iv i ​ v, start subscript, i, end subscript down a road with two curves. The first

curve has a radius RRR and the second curve has a radius 3R3R3, R. How does the magnitude of the truck's centripetal acceleration change after the radius increases? Choose 1 answer: Choose 1 answer: (Choice A) A Increases by factor of 333 (Choice B) B Decreases by factor of 999 (Choice C) C Decreases by factor of 333 (Choice D) D No change
Physics
1 answer:
Alex3 years ago
7 0

Answer:

(C) Decreases by factor of 3

Explanation:

Centripetal acceleration is given by

a = \dfrac{v^2}{r}

where <em>v</em> is the linear velocity and <em>r</em> is the radius of the curve.

Let the centripetal acceleration on the curve of radius <em>R</em> be a_1.

Then

a_1 = \dfrac{v_i^2}{R}

Let the centripetal acceleration on the curve of radius 3<em>R</em> be a_2.

Then

a_2 = \dfrac{v_i^2}{3R} = \dfrac{1}{3}\dfrac{v_i^2}{R} = \dfrac{1}{3}a_1

Here, we see that the acceleration decreases by a factor of 3.

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