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kari74 [83]
2 years ago
9

? What is the magnitude of force required to accelerate a car of mass 1.7 × 103 kilograms by 4.75 meters/second2

Physics
2 answers:
KIM [24]2 years ago
4 0

f=ma

f=175.1*4.75m/s

f= 831.725N

densk [106]2 years ago
4 0

Answer:

F=8075 N

Explanation:

The second newton's law state the relation between the force and the acceleration by the formula:

F=m.a

Where F is the force, m is the mass and a is the acceleration.

It is known that the mass of this car is 1.7x10^3 kg and its acceleration is 4.75 m/s^2. Replacing in the formula:

F=(1.7x10^3 kg)(4.75 m/s^2)

F=8075 N

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An object, when pushed with a net force F, has an acceleration of 4 m/s . Now twice the force is applied to an object that has f
hjlf

Answer:

B. 2 m/s

B. Acceleration = 4.05 m/s² and Tension = 297.5 N.

Explanation:

A force is applied on a mass m whose acceleration is 4 m/s

Force = mass × acceleration

a = F/m = 4 m/s

4 m/s = F/m

F = 4 m/s (m)

If  Force of 2F is applied on a mass of 4m ; it acceleration is as follows:

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4m/s (m) / 2m = 2 m/s

a = 2 m/s

2.

Given that

mass m_1 = 30 kg

mass m_2 = 50 kg

\mu = 0.1

From the question; we can arrive at two cases;

That :

m_{2} a _ \ {net} }= m_2g - T   ----- equation (1)

m_{1} a _ \ {net} }=  T - mg sin \theta  - F ---- equation (2)

50 a = 50 g - T

30 a = T - 30 g sin 30 - 4 × 30 g cos 30

By summation

80 a =[ 50  - 30 * \frac{1}{2} - 0.1 *30* \frac{\sqrt{3}}{2}]g

80 a = 32. 4 × 10 m/s ²  (using g as 10m/s²)

80 a = 324 m/s ²

a = 324/80

a = 4.05 m/s²

From equation , replace a with 4.05

50 × 4.05 = 50 × 10 - T

T = 500 -202.5

T =297.5 N

8 0
3 years ago
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Answer:

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heavier load the parachute must be moving faster to match the downward force of the greater load

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