3 years ago

I dont know please help and show your work

Mathematics

1 answer:

Phoenix [80]3 years ago

4 0

Area=6x10=60 feet as it is rectangle so all angles are 90° and oppossite sides are equal

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In ABC,if sin A=4/5 and tan A=4/3, then what I s cos A?

Svet_ta [14]

Cos(A) will be 3/5 Cos(A) is adjacent/hypotenuse. So here we have sin(A)=opp/hyp which is 4/5 and tan(A)=opp/adj which is 4/3. So cos(A) is adj./hyp and knowing the previous 2 terms of sin(A) and cos(A), you can go ahead and find Cos(A). So cos(A) is 3/5

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3 years ago

What is the vertex form of y=x^2+14x+50 and how do u get it?

valkas [14]

(x`-b/2a)-D/4a
(x`-7)+576
answer! (7;-576)

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3 years ago

(ax-b)(bx+a)=(bx^2+a)a make x subject of the formula

Dmitriy789 [7]

Answer:hehe

Step-by-step explanation:

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3 years ago

What is the value of x?<br> Please show the steps

nordsb [41]

Let D be the endpoint of the angle bisector opposite A on lying on side BC. The angle bisector theorem states that the ratio of BD to CD is equal to the ratio of AB to AC. In this case, you have

$\dfrac{2x-1}{3x}=\dfrac9{15}$

(This is the same equation that you have, it's just rearranged.)

Multiply both sides by $3x$ and 15.

$15\times3x\times\dfrac{2x-1}{3x}=15\times3x\times\dfrac9{15}$
$15(2x-1)=3x\times9$

Now you can solve for $x$ .

$30x-15=27x$
$3x=15$
$x=5$

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3 years ago

I need help on this please

Romashka [77]

Answer:

with what

Step-by-step explanation:

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3 years ago