I dont know please help and show your work

Mathematics

1 answer:

Phoenix [80]4 years ago

4 0

Area=6x10=60 feet as it is rectangle so all angles are 90° and oppossite sides are equal

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#10 There are 16 girls in

mihalych1998 [28]

Answer:

45.71% I think I'm not sure

Step-by-step explanation:

this equation was tough I dont have an explanation

7 0

3 years ago

Find the roots of the quadratic equation x^2 – 8x = 9 by completing the square. Show your work.

loris [4]

X² - 8x = 9
x² - 8x - 9 = 0
x² + x - 9x - 9 = 0
x(x + 1) -9(x + 1) = 0
(x+1)(x-9) = 0
x = -1 or 9

In short, Your Answers would be -1 & 9

Hope this helps!

3 0

3 years ago

(problem 83)

AVprozaik [17]

To find the derivative of this function, there is a property that we should know called the Constant Multiple Rule, which says:

$\dfrac{d}{dx}[cf(x)] = cf'(x)$ (where $c$ is a constant)

Remember that the derivative of $\csc(x)$ is $-\csc(x)\cot(x)$ . However, you may notice that we are finding the derivative of $\dfrac{1}{2}\csc(2x)$ , not $\dfrac{1}{2} \csc(x)$ . So, we are going to have to use the chain rule. To complete the chain rule for the derivative of a trigonometric function (in layman's terms) is basically the following: First, complete the derivative of the trig function as you would if what was inside the trig function is $x$ . Then, take the derivative of what's inside of the trig function and multiply it by what you found in the first step.

Let's apply that to our problem. Right now, I am not going to worry about the $\dfrac{1}{2}$ at the front of the equation, since we can just multiply it back in at the end of our problem. So, let's examine $\csc(2x)$ . We see that what's inside the trig function is $2x$ , which has a derivative of 2. Thus, let's first find the derivative of $\csc(2x)$ as if $2x$ was just $x$ and then multiply it by 2.

The derivative of $\csc(2x)$ would first be $-\cot(2x)\csc(2x)$ . Multiplying it by 2, we get our derivative of $-2\cot(2x)\csc(2x)$ . However, don't forget to multiply it by the $\dfrac{1}{2}$ that we removed near the beginning. This gives us our final derivative of $-\cot(2x)\csc(2x)$ .

Remember that we now have to find the derivative at the given point. To do this, simply "plug in" the point into the derivative using the x-coordinate. This is shown below:

$-\cot[2(\dfrac{\pi}{4})]\csc[2(\dfrac{\pi}{4})]$