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Mamont248 [21]
4 years ago
12

(x-2)(x+2) Find The Product?

Mathematics
2 answers:
yKpoI14uk [10]4 years ago
5 0
(x-2)*(x+2) = x*(x+2) - 2*(x+2)

<span>(x-2)*(x+2) = x*x + x*2 - 2*x - 2*2
</span>
<span>(x-2)*(x+2) = x^2 + 2x - 2x - 4
</span>
<span>(x-2)*(x+2) = x^2 - 4
</span>
That's the long way to do it. You can use the difference of squares formula as a shortcut

(a-b)*(a+b) = a^2 - b^2

(x-2)(x+2) = x^2 - 2^2

<span>(x-2)(x+2) = x^2 - 4
</span>
either way, the final answer is x^2 - 4
jekas [21]4 years ago
4 0
(X-2)(x+2)
So use "f.o.i.l" meaning you multiply each first term, the outside terms, the inside terms and last terms, and then add. You'd get x^2-4 in this example
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The midpoint AB is M (-1,1). If the coordinates of A are (-6,-3), what are the coordinates of B
Ratling [72]

Answer:

coordinates of B is ( 4,5)

Step-by-step explanation:

If there two points (x1,y1) and (x2,y2) on a plane then coordinates of mid point is given by

m = (x1+x2)/2  , (y1+y2)/2

Given

m = (-1,1)

A= (-6, -3)

we have to point b

let point b be (x,y)

Then m (-1,1) is given by (-6+x)/2 , (-3+y)/2

(-6+x)/2 = -1

-6 + x = 2*-1 = -2

x = -2+6 = 4

also

(-3+y)/2 = 1

=> -3 + y = 2

=> y = 2 + 3 = 5

Thus , coordinates of B is ( 4,5) answer

5 0
3 years ago
Can somebody explain to me how to find vertex form from a graph?? I put an example graph if you need it :)))
kifflom [539]

Answer:

y = - 4(x + 3)² + 7

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

From the graph (h, k ) = (- 3, 7 ), thus

y = a(x + 3)² + 7

To find a we require a point on the graph other than the vertex

Using (- 2, 3) , substitute into the equation

3 = a(- 2 + 3)² + 7

3 = a + 7 ( subtract 7 from both sides )

a = - 4

Thus

y = - 4(x + 3)² + 7 ← in vertex form

8 0
3 years ago
Burt's burger barn sold 495 hamburgers today. The number sold with cheese was half the number sold without cheese. How many of e
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kykrilka [37]
UPWARD JOURNEY
(g is -ive)
u= 80.5m/s
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(g is +ive)
u=0
We need to find the velocity at 89m from ground, which is equivalent to finding velocity at 325 m from the topmost point in downward direction.

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3 years ago
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