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IgorLugansk [536]
2 years ago
5

Slope of 4/5, a width of 30…what is the height..?

Mathematics
1 answer:
maw [93]2 years ago
8 0

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

Slope of the graph can be expressed as :

\qquad \sf  \dashrightarrow \:slope =   \tan( \theta)  =  \dfrac{4}{5}

\qquad \sf  \dashrightarrow \:   \dfrac{x}{30}  =  \dfrac{4}{5}

\qquad \sf  \dashrightarrow \: x =  \dfrac{4}{5}  \times 30

\qquad \sf  \dashrightarrow \: x =  {4}{}  \times 6

\qquad \sf  \dashrightarrow \: x = 24 \: units

So, the value of x is 24 units

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djverab [1.8K]

Answer:

I think it's 3,6.....................

4 0
3 years ago
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A rectangular prism has a volume of 360 in3. If the height measures 6in. which base measurements could the prism have?
Daniel [21]

Answer:

Both sides that are parallel ( 6 inches I believe ) would be 12 in total for both sides. Then the top and bottom would be 3 inches ( I believe ) which would be 6. I think you need to do 6 times 12 until you get 360 and then see how many times you multiplied it and that is your answer. But I am not FULLY sure. Hope this helps somehow!

Step-by-step explanation:

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3 years ago
Convert y=9 from rectangular to polar form
Crazy boy [7]

Answer:

r = 9/sin Ф or r = 9 csc Ф

Step-by-step explanation:

The polar form is represented as:

x = r cos Ф and

y = r sin Ф

We are given:

y = 9

Putting value in y = r sin Ф

9 = r sin Ф

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5 0
3 years ago
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Help help help thanks
bija089 [108]
The answers are C and E,
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7 0
3 years ago
A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel
Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

x_{Sh} = x_{o} + v_{Sh}\cdot t

Submarine

x_{Su} = x_{o}+v_{Su}\cdot t

Where:

x_{o} - Position of Diego Garcia island, measured in miles.

x_{Sh}, x_{Su} - Current positions of ship and submarine, measured in miles.

v_{Sh}, v_{Su} - Velocities of ship and submarine, measured in miles per hour.

t - TIme, measured in hours.

If we know that x_{Sh} - x_{Su} = 241\,mi, v_{Sh} = 19\,\frac{mi}{h} and t = 7\,h, then:

x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t

We clear now the velocity of submarine:

\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}

v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}

v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}

v_{Su} = -15.429\,\frac{mi}{h}

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

4 0
3 years ago
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