If there is a solution(s) they will be the point(s) of intersection on the graph.
If there are infinite solutions there will be only one line or curve.
If the lines are parallel there is no solution.
<span>y = 2 for x < 0
= x for 0 ≤ x < 3
= 3 for x ≥ 3 </span>
Answer:
1/52
Step-by-step explanation:
4/208=1/52
We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
</span>
Answer:
The fraction of horses that are Morgan's=17/20
Step-by-step explanation:
Step 1: Determine fraction for each breed
Arabians=1/4
Thoroughbreds=2/5
Morgan's=unknown
Step 2: Express each breed as a fraction of the total
Number of Arabians=fraction of Arabians×total number of horses
Let total number of horses be x
Arabians=(1/4)×x=1/4 x
Thoroughbreds=(2/5)×x=2/5 x
Morgans's=m
Step 3: Calculate fraction of Morgans
Total number of horses=Arabians+Thoroughbreds+Morgans
x=(1/4)x+(2/5)x+m
solve for m;
m=x-(1/4)x-(2/5)x
m=x-3/20x
m=17/20 x
The fraction of horses that are Morgan's=17/20
