Length of one edge is 10cm
And the surface area is 600cm2
Initial velocity of John's car (V1) = 0 miles per hour
Final velocity of John's car (V2) = 45 miles per hour
Time taken for acceleration = 45 seconds
Then
Acceleration = (V2 - V1)/Time taken
= (45 - 0)/15 miles per hour per second
= 45/15 miles per hour per second
= 3 miles per hour per second.
So the approximate rate of change in the miles per hour that John's car accelerated is 3 miles per hour per second. The correct option among all the options given in the question is option "A".
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Step-by-step explanation:
interchanging the variables
x = 5y^2 + 10
5y^2 +10 = x
5y^2 = x - 10
dividing by 5
5y^2/5 = x/5 + -10/5
y^2 = x/5 + - 10/5
y^2 = x/5 - 2
y = 5 (x-10) 0/5 (sq.rt)
g(5x^2 + 10) = 5x/5
g(5x^2 + 10) = x
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Answer:
1000 in
Step-by-step explanation:
Given
The dimension of the small cube is 1\ in.1 in.
No of the cubes is 10^6106
If the small cubes are arranged on the floor
The area of the cubes is
\Rightarrow 10^6\times 1^2\ in.^2⇒106×12 in.2
