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Alla [95]
3 years ago
11

The diagonals of a Rhombus are 2Dm and 3M. What’s is the area of the Rhombus??

Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

336m^{2}

Step-by-step explanation:

Area of Rhombus = (1/2)*xy

Where x and y are length of diagonals

Area = (1/2) * 21 * 32 = 21* 16 = 336

Area = 336 m²

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If US=52, ST=30, UT=40, VW=27, and XW=36, find the perimeter of ΔVWX. Round your answer to the nearest tenth if necessary. Figur
Ierofanga [76]

Answer:

The perimeter is 109.8

Step-by-step explanation:

As we can see here, the angles of the triangles are congruent so we can say that both triangles are congruent

When two triangles are congruent, the ratio of their corresponding sides are equal

So we can get the scale factor here by looking at the sides facing each specific angle in both triangles

In the bigger triangle,

The side facing 34 degrees has a length of 30

In the smaller triangle,

The side facing 34 degree has a length of 27

So the scale factor to get the smaller from the bigger is 27/30 = 9/10 or 0.9

Likewise the side facing 51 degrees in the bigger is 40 while for the smaller, it is 36

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2 years ago
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