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Alla [95]
4 years ago
11

The diagonals of a Rhombus are 2Dm and 3M. What’s is the area of the Rhombus??

Mathematics
1 answer:
NemiM [27]4 years ago
7 0

Answer:

336m^{2}

Step-by-step explanation:

Area of Rhombus = (1/2)*xy

Where x and y are length of diagonals

Area = (1/2) * 21 * 32 = 21* 16 = 336

Area = 336 m²

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Convert 0.25 to a fraction in its simplest form​
erik [133]

Answer: 1/4 is the answer

Step-by-step explanation: it is 1/4 because 25/100 = 1/4

may i have brainiest plz i have like 1 or something

8 0
3 years ago
F(x)=4^x and g(x)=4^x+2
dsp73

Given:

The two functions are:

f(x)=4^x

g(x)=4^x+2

To find:

The type of transformation from f(x) to g(x) in the problem above and including its distance moved.

Solution:

The transformation is defined as

g(x)=f(x+a)+b                .... (i)

Where, a is horizontal shift and b is vertical shift.  

  • If a>0, then the graph shifts a units left.
  • If a<0, then the graph shifts a units right.
  • If b>0, then the graph shifts b units up.
  • If b<0, then the graph shifts b units down.

We have,

f(x)=4^x

g(x)=4^x+2

The function g(x) can be written as

g(x)=f(x)+2            ...(ii)

On comparing (i) and (ii), we get

a=0,b=2

Therefore, the type of transformation is translation and the graph of f(x) shifts 2 units up to get the graph of g(x).

3 0
3 years ago
1. In the given figure O is the centre and PQ is the diameter of the circle. if the chord PR is produced to S and QR is joined t
Ksenya-84 [330]

Answer:

90°

Step-by-step explanation:

since PQ is the diameter of the circle, m <em>L</em><em> </em>PRQ = ½ × 180° = 90°.

so, as a supplementary to <em>L</em><em> </em>PRQ, the value of angle QRS = 180 - m <em>L</em><em> </em>PRQ = 180-90 =90°

5 0
3 years ago
Show work
Maru [420]
Area of circle = πr²
Area of circle = π x 12 x 12 
Area of circle = 452.4cm² (nearest tenth)
7 0
4 years ago
Can someone help me with this question: What is the 40th term of these sequences below. 13, 26, 39, 52,...... 6, 12, 18, 24,....
Nina [5.8K]

Answer:520; 240

Step-by-step explanation:

a. 13, 26, 39, 52,......

a = First term = 13

d = common difference = 26 - 13 = 13

40th term = a + (n - 1)d = a + (40-1)d = a + 39d

= 13 + (39 × 13)

= 13 + 507

= 520

b. 6, 12, 18, 24,.......

a = First term = 6

d = common difference = 12 - 6 = 6

40th term = a + 39d

= 6 + 39(6)

= 6 + 234.

= 240

8 0
3 years ago
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