Jodie ran at an average speed of 8 km/h for 30 minutes. How far did she run in km?

Complete the following proof.

timofeeve [1]

Statement:

1. RS tangent to Circle A and Circle B at points R and S

2. AR ⊥ RS, BS ⊥ RS

3. AR ║ BS

Reason:

1. Given

2. Radius ⊥ to tangent

3. 2 lines ⊥ to same line are ║

100% Correct

~Hope it helps~ :)

4 0

3 years ago

Read 2 more answers

Maths help please!!!!!! PART B ONLY

andreyandreev [35.5K]

Answer:

19.37.

Step-by-step explanation:

Integrating the function we get

x^4/4 - 5x^3/3 + x^2 + 8x

Area under the curve from x = -1 to x = 0

= (-1)^4/4 - 5(-1)^3/3 + (-1)^2 - 8

= 5.083

In a similar way we calculate area from 0 to 2

this = 10.667.

Total = 15.75.

Now we subtract 12.13 to get the area from x = 2 to x =p.

= 15.75 - 12.13 = 3.62

So total shaded area = 15.75 + 3.62

= 19.37.

5 0

2 years ago

SOLVE THIS EXTREMELY IMPORTANT EQUATION

finlep [7]

Answer:

Option B; EF = ( About ) 4.47 units, Perimeter of Δ EFG = ( About ) 12.94 units

Step-by-step explanation:

If we were to consider the height of this triangle EFG, it would be 4 units of length, supposedly splitting base GF into two ≅ parts, each 2 units of length. First let us name the point drawn to base GF ⇒ point H, so that the height of Δ EFG ⇒ EH. Now as EH splits GF into two ≅ parts, by Converse to Coincidence Theorem, Δ EFG ⇒ Isosceles Δ;

EH and FH are legs of a right triangle EFH, so that Pythagorean Theorem can be applied to solve for the length of EF and EG, knowing that as Δ EFG ⇒ Isosceles Δ, EF ≅ EG;

( EH )^2 + ( FH )^2 = ( EF )^2,

( 4 )^2 + ( 2 )^2 = ( EF )^2 ⇒ take square of 4 & 2,

16 + 4 = ( EF )^2 ⇒ combine like terms,

( EF )^2 = 20 ⇒ take square root on either side to solve for EF,

EF = √ 20 = ( About ) 4.47 units = EG,

Perimeter of Δ EFG = EF + GF + EG = 4.47 + 4 + 4.47 = ( About ) 12.94 units,

Solution; Option B

6 0

3 years ago

Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye

slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.