All categories

2 years ago

Simplify for this question !

Mathematics

2 answers:

aalyn [17]2 years ago

7 0

Answer:

6x^3

Step-by-step explanation:

PolarNik [594]2 years ago

6 0

Answer:

=6x^9-3 [12/2=6]

=6x^6

You might be interested in

If f(x)=3x-7, find f(x)=2

Arisa [49]

Answer:

x = 2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Last month Dory biked 11 times as many miles as Carly together dirt bike the total of 156 miles how many miles did Dory biked la

Lynna [10]

I don't know. check google!

8 0

3 years ago

I need help with 5&6 please ASAP!!!!!!!

Elenna [48]

Hi BFFF IM MDJXJCNDM

4 0

2 years ago

Read 2 more answers

*see attached image*

Leni [432]

Answer:

Sin, Cos, Tan and others are used to calculate the ratios of the sides of a right angled triangle by taking a certain angle as the angle of reference.

On the other hand, Sin‐¹, Cos‐¹ and Tan-¹ are used to find the reference angle used to calculate the ratio of sides.

For this question,

we need to find which option should used to calculate the angle the slide makes with the vertical support.

So the option will have to be either A, C or E.

here, the base is 2.81m and hypotenuse is 3.64m.

we know, Cos = base / hypotenuse

So the angle is given by Cos-¹(2.81/3.64)

Option C

4 0

2 years ago

Read 2 more answers

An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15

NeTakaya

Answer:

D. 22,417 feet

Step-by-step explanation:

Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.

Hypotenuse = x and Opposite = 15,000feet

According to SOH;

$sin 42^0 = \frac{Opposite}{Hypotenuse} \\\\Sin42^0 = \frac{15000}{x}\\ \\x = \frac{15000}{sin42^0}\\\\ \\$

$x = \frac{15000}{ 0.6691} \\\\x = 22,417 feet$

Hence the distance (x) from the plane P to the observer O is approximately 22,417 feet

3 0

3 years ago