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3 years ago

5

ANSWER ASAPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

Semmy [17]3 years ago

3 0

I Believe the answer is B. 2b²-3

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Brielle made a color using 2 cups of white paint and 3

Rudiy27

Answer:

she should mix 6 cups of green paint with 4 cups of white paint

Step-by-step explaination:

you are just multiplying by 2. 2 times 2=4 cups of white paint. So the same thing you do to both sides, 2 times 3=6

so the answer is 6 cups of green paint

4 0

3 years ago

Question in the image below:

horrorfan [7]

Answer:

x = 5/33 or 0.151515151

Step-by-step explanation:

7(-6x-2) = 8(3x-4)

step 1: simplify the equation.

-42x - 14 = 24x - 4

step 2: isolate the variable (using the balance method).

-42x - 14 + 14 = 24x - 4 + 14

-42x = 24x + 10

-42x - 24x = 24x - 24x + 10

-66x = 10

step 3: solve for x.

x = 10 ÷ -66

x = 5/33

4 0

3 years ago

7. Find DE.<br> 11-25<br> E<br> А<br> 4x + 1<br> D<br> С

Arlecino [84]

Answer:

DE = 37

Step-by-step explanation:

AD = DC and BE=EC ⇒

DE = 1/2AB

4x + 1 = 1/2(11x - 25)
2(4x + 1) = 11x - 25
8x + 2 = 11x - 25
11x - 8x = 2 + 25
3x = 27
x = 27/3
x = 9

DE = 4*9 + 1 = 36 + 1 = 37

3 0

3 years ago

Read 2 more answers

The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviat

aleksley [76]

Answer:

4.5 hour and 2 hour

Step-by-step explanation:

Given: The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviation of two hours.

To Find: If each time was increased by one hour, what would be the new mean and standard deviation.

Solution:

let the total numbers entries of hours in survey be = $\text{N}$

each entry in survey be = $\text{x}_{i}$

mean of survey is = $\mu$ = $3.5$ $\text{hours}$

standard deviation is = $\sigma$ = $2$ $\text{hours}$

if each entry in survey is increased by one hour then,

each new entry in survey is = $\text{x}_{i}+1$

the new mean is $\mu_{new}$ = $\frac{\text{sum of all hours}}{total number of entries}$

$\frac{\text{x}_{1} +1+\text{x}_{2}+1 +....+\text{x}_{N}+1 }{N}$

$\frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})+\text{N}\times1 }{N}$

$\frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})}{N}$ + $\frac{\text{N}\times1 }{N}$

$\mu_{new}$ = $\mu$ + 1= $4.5$ $\text{hours}$

now,

standard deviation is $\sigma_{new}=$ $\sqrt{\sum_{1}^{N}\frac{(\text{x}_{inew}-\mu_{new})^{2}}{N}}$

$\text{x}_{inew}= \text{x}_{i}+1$

$\mu_{new}=\mu+1$

putting values,

$\sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}+1-\mu-1)^{2}}{N}}$

$\sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}-\mu)^{2}}{N}}$ = $\sigma$

$\sigma_{new}$ =2

new mean and standard deviation are $4.5$ and $2$ $\text{hours}$

5 0

3 years ago

Need help for an assignment please and thank you.

BARSIC [14]

Answer: $130.9^{\circ}$

Step-by-step explanation:

Given

The number of students in the first year is 800

The number of students in the second year is 950

The number of students in the third year is 1000

If this data is graphed on a pie chart, then the area percentage of area occupied by third years is

$\Rightarrow \dfrac{1000}{1000+950+800}\times 100=36.36\%$

Now, the angle around the center of the circle is $360^{\circ}$

$\therefore \text{angle covered by third years=}0.3636\times 360^{\circ}\\\Rightarrow 130.896\approx 130.9^{\circ}$

6 0

3 years ago