Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
Answer:
There are no graphs, but the graph should look lyke this:
An open circle on the point "10"
And from the 10, the arrow should be going left, towards the negatives, or smaller numbers than the ten
Answer:
Step-by-step explanation:
A)
(22+12)/2 = [17] (12+17)/2 = [14.5] (17+14.5)/2 = [15.75]
B)
(10.5*2) - 5 = [16] ......... NOT 13
|-13+2| is 11 and |10+1| is 11, so yes they are equal
Answer:
5+1=6
5/6 x420
5x70=350
Step-by-step explanation:
