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3 years ago

Solve for the following y: -6x +2y=8

Mathematics

2 answers:

frosja888 [35]3 years ago

3 0

-4/3+1/3y I hope thats right

Nonamiya [84]3 years ago

3 0

Y = 3x+4 is the answer to the following.

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Help if you can. Thank You.

Anna35 [415]

Answer:

$Given:-$ Δ ABC

$AC~is~exteuded ~through ~C~to ~D$

$BC~is ~drawn ~to ~AC$

$Using ~Triangles~Exterior~angle~theorm,$

1) =∠3+∠4 and ∠4=∠5+∠6

∠7=∠3+∠2

So, only D) m∠7=m∠3+m∠2 is correct

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hope it helps..

have a great day!!

8 0

3 years ago

Consider the right triangle. A right triangles with side lengths 28 meters and 45 meters. The hypotenuse is unknown. What is the

omeli [17]

Answer:

The answer is 53 or Square Root (sqrt) of 2809

Step-by-step explanation:

a^2+b^2=c^2

28^2+45^2=c^2

784+2025=c^2

c^2=sqrt 2809

c = 53

8 0

3 years ago

Read 2 more answers

The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in

Stolb23 [73]

Answer:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=34.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=300-1=299$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that $t_{\alpha/2}=1.653$