Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
Answer:
to big but i will slove it for u ok so see solution c one is correct
Answer:
1 solution
Step-by-step explanation:

The output is the cute of the input is written as y = x³.
Answer:

Step-by-step explanation:
Let the equation of the perpendicular line is,
y = mx + b
where m = slope of the line
b = y-intercept
From the graph, slope of the line passing through (0, -1) and (3, 1),
m' =
m' = 
m' = 
To get the slope (m) of this line we will use the property of perpendicular lines,
m × m' = (-1)
m ×
= -1
m = 
Equation of the perpendicular line will be,

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)
0 = 
b = 
Equation of the line will be,
