You use the quotient rule for derivatives since you are dividing. We will use F(x) for sinx and G(x) for (1+tanx), and H'(x) for the final answer. So H'(x) = (F'(x)G(x) - F(x)G'(x))/(G(x))^(2)) The derivative of sinx is cosx so F'(x) = cosx The derivative of 1+tanx is sec^(2)x, just like the derivative of tangent (because the derivative of a constant is 0, and by the addition rule for derivatives you would add the derivatives). 0 + sec^(2)x is sec^(2)x. So G'(x) is sec^(2)x. So with this information just plug F, F', G, and G' into the H'(x) = (F'(x)G(x) - F(x)G'(x))/(G(x))^(2)) equation and solve. H'(x) = (cosx)(1+tanx) - (sinx)(sec^(2)x)/((1+tanx)^(2))
You basically just split it right down the middle. if the cost of something is lets say $75.58, then you would divide 75.58 by 2, which is $37.79 hope it helps!!
since it's 400 a week then you need to take into account the weeks worked. Then since it's 50 per an appliance you need to multiply by the number sold.
