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3 years ago

Please Help Me ASAP.

Mathematics

1 answer:

garri49 [273]3 years ago

7 0

Answer:

Parallel lines ALWAYS have the same slope

Step-by-step explanation:

The equations have unequal slopes, meaning they aren't parallel.

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1x10 to the fifth power over 4x10 to the negative faith power given on scientific notation

MissTica

Answer:

$2.5*10^{8}$

Step-by-step explanation:

<u><em>The correct question is</em></u>

1x10 to the fifth power over 4x10 to the negative fourth power given on scientific notation

we know that

To divide two numbers in scientific notation, divide their coefficients and subtract their exponents.

we have

$\frac{1*10^{5}}{4*10^{-4}}=(\frac{1}{4})*10^{5+4} =0.25*10^{9}= 2.5*10^{8}$

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3 years ago

Jonathan budgeted $250.00 for plants, sets, and seeds for his garden. After reading through his planting guides, he realized he

Murljashka [212]

Answer:I believe 37.25

Step-by-step explanation:

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3 years ago

Please please help me with this

iris [78.8K]

Answer:

angle FQE= Minor sector

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3 years ago

The system of equations Y =-3x+2 and Y = 3x-6 is shown on the graph below.

Ira Lisetskai [31]

Answer:

Step-by-step explanation:

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3 years ago

If cot theta= 4/3, find csc theta

Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

$csc^2\theta=cot^2\theta+1$

Knowing that $cot\theta=\frac{4}{3}$ :

Substitute it into $csc^2\theta=cot^2\theta+1$ :

$csc^2\theta=(\frac{4}{3})^2+1$

Simplify the expression:

$csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}$

Solve for $csc\theta$ . Apply square root at both sides of the expression:

$\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}$

$csc\theta=\frac{5}{3}$

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3 years ago