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3 years ago

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How to count fast from 82-199

1 answer:

boyakko [2]3 years ago

3 0

Just skipppppp counttttt

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At one farmer’s market, bananas cost $0. 80 per pound. At another farmer’s market, bananas are sold in 5-pound bags for $4. 50 p

Minchanka [31]

To find the better buy divide 4.50 by 5 to find the unit rate for the 5-pound bag, and compare that number to $0. 80 per pound.

<h3>What is cost price per pound?</h3>

The cost price per pound is the amount of money required to buy one pound of a brand or goods.

To find the cost price per pound, divide the total amount of cost of the goods to the total number of goods.

At one farmer’s market, bananas cost $0.80 per pound.

At another farmer’s market, bananas are sold in 5-pound bags for $4. 50 per bag. To compare it with first market price, divide the 5 pound bags with $4.50.

The cost of one bag in this market is,

$C=\dfrac{4.50}{5}\\C=0.5625$

As this cost is less, thus, the cost of this market for one banana is less than the first market and so this is the better buy.

Hence, to find the better buy divide 4.50 by 5 to find the unit rate for the 5-pound bag, and compare that number to $0. 80 per pound.

Learn more about the cost price per pound here;

brainly.com/question/20333618

4 0

2 years ago

Directions: Simplify the following monomials.SHOW THE STEPS!

Pavel [41]

Answer:

I hope you enjoy it if you have any questions ask me

4 0

2 years ago

Read 2 more answers

Erin invested 15000 some at 5 percent and some at 8 percent annual interest if she recieves an annual return of 930 dollars how

eduard

.08x+.05(15000-x)=930
.08x+750-.05=930
.08x-.05x=930-750
.03x=180
X=180/.03=6,000 at 8%
(15000-6000)=9000 at 5%

8 0

3 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

Complete the statements.<br> f(4) is<br> f(x) = 4 when xis

inessss [21]

Think about this as a table of values where domain is the x values and range is the y values.

f(4) wants the y-value when the x-value is 4

f(4) = 1/2

The second question wants us to find the x-value when f(x) also known as the y-value is 4.

f(x) = 4

x = 8

answers: 1/2, 8

6 0

3 years ago

Read 2 more answers