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3 years ago

8

Mese questions are based on a 52

1 answer:

Mrrafil [7]3 years ago

5 0

Answer:1.) 6/52

Step-by-step explanation:

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Svetlanka [38]

Answer:

$(f\cdot g)(x)=2x^2+10x+12$

$(f-g)(x)=-x-1$

$(f+g)(1)=10$

Step-by-step explanation:

$\tt f(x)=x+3$

$\tt g(x)=2x+4$

$(f\cdot g)(x)=f(x)\cdot g(x)=(x+3)(2x+4)=2x^2+4x+6x+12$

$=2x^2+10x+12$

$(f-g)(x)=f(x)-g(x)=x+3-(2x+4)=x+3-2x-4$

$=-x-1$

$(f+g)(1)=f(1)+g(1)=1+3+2(1)+4$

$=4+2+4=10$

~

7 0

2 years ago

Ashley deposited $4,000 into a savings account that earns 4% simple interest. How much interest did she earn after three years?

Vinil7 [7]

Answer:

for the 1st year she earned 160 so for 3 years she will earn $480

6 0

3 years ago

Shane downloaded 5 songs in two minutes At this rate, how many songs can he download in ½ hour?

MissTica

Answer:

75

Step-by-step explanation:

he can download 2.5 songs per minute so 2.5 x 30 is 75

3 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL MARK BRAINLIEST

krok68 [10]

Answer:

Option 2

Step-by-step explanation:

Because it shows that it is going up in a half not a whole.

3 0

3 years ago

Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants

musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error for the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.22$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample should she take?

We need a sample size of at least n.

n is found when $M = 0.02$

So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}$

$\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}$

$n = 1160.88$

Rounding up

We need a sample size of at least 1161.

7 0

3 years ago