All categories

2 years ago

Pls help to get 100points

Mathematics

2 answers:

Ghella [55]2 years ago

5 0

Answer:

Please mark me brainliest and I hope this helped!

7/3

Step-by-step explanation:

To get the answer, we add all of the numerator numbers together since the denominators are all the same. 3 + 4 + 7 = 7 + 7 = 14

The answer is 14/6. We can then simplify it and divide both the numerator and the denominator by 2. That gives us 7/3 and that is our final answer.

Lesechka [4]2 years ago

3 0

The answer is attached to the picture .

Step-by-step explanation:

hope it helps !!

You might be interested in

Somebody guess my fav color Guess right get brainliest

Tju [1.3M]

Step-by-step explanation:

Blue is your favorite color?

7 0

2 years ago

Read 2 more answers

Myranda received a movie gift card for $100 to her local theater Matinee tickets cost $7.50 each and evening tickets 12.50 each

Rama09 [41]

Answer:

Divide them both by 100

Step-by-step explanation:

3 0

2 years ago

HURRRRRY question is is pdf file below which is the correct answer?

Mekhanik [1.2K]

Answer: 875

Step-by-step explanation:

5 0

11 months ago

Any 10th grader solve it for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$