The series is an arithmetic series with first term -10 and common difference (-2-(-10))=8. The general term a_n can be written as
a_n = -10 + 8(n-1)
or
a_n = -18+8n
The last term corresponds to
110 = -18+8n
128 = 8n
16 = n
So, the summation can be written as
Answer:
a = 25 , b = 14
Step-by-step explanation:
For A
a/5 + 3 = 8
a/5 = 8 - 3
a/5 = 5
Cross multiply
a = 5 * 5
a = 25
For B
3b/7 - 1 = 5
3b/7 = 5 + 1
3b/7 = 6
Cross multiply
3b = 42
b = 42 / 3
b = 14
Hope it will help
Hello!
In a function, each input has only one output. In A, three has two outputs, 4 and 5, so A is not a function.
In B, you can use something called the vertical line test to see if each x value has one y value as an output. You move an imaginary vertical line across the graph, and if it intersects with two points it is not a function. If we do this on our graph, it will not intersect two points. Therefore, B is a function.
In C, we can see that each input has one output, or there are all different inputs, so C is a function.
For D we can use that vertical line test again. It intersects both the points (-1,1) and (-1,6) so D is not a function
Our final answers are B and C.
I hope this helps!
Answer:
The standard deviation of number of hours worked per week for these workers is 3.91.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem we have that:
The average number of hours worked per week is 43.4, so
.
Suppose 12% of these workers work more than 48 hours. Based on this percentage, what is the standard deviation of number of hours worked per week for these workers.
This means that the Z score of
has a pvalue of 0.88. This is Z between 1.17 and 1.18. So we use
.





The standard deviation of number of hours worked per week for these workers is 3.91.
Not sure if you wanted answers or explanation on what to do. Ill just do the explanation and if you want the answers just lmk C:
R=1/2 d, and C=pi*2r. So you basically take the given number and plug it into these formulas.