Answer:
x = 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2(x + -5) + x = x + (-6)
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property] Distribute 2: 2x - 10 + x = x - 6
- [Addition] Combine like terms (x): 3x - 10 = x - 6
- [Subtraction Property of Equality] Subtract <em>x</em> on both sides: 2x - 10 = -6
- [Addition Property of Equality] Add 10 on both sides: 2x = 4
- [Division Property of Equality] Divide 2 on both sides: x = 2
Answer:
0
Step-by-step explanation:
Since as of now we're saying that the probability of having a girl is 1/2, we can say:
1/2 * 1/2 * 1/2 * 1/2, because then you're saying a one half chance of having a girl times another one half chance of having a girl, etc.
That ends up to be 1/16.
Probability that a student will play both is 7/30
Step-by-step explanation:
Total students = 30
No. of students who play basketball = 18
Probability that a student will play basketball = 18/30
= 3/5
No. of students who play baseball = 9
Probability that a student will play baseball = 9/30
= 3/10
No. of students who play neither sport = 10
Probability that a student will play neither sport = 10/30
= 1/3
To find :
Probability that a student will play both = p(student will play both)
No.of students who play sport = 30 - 10
= 20
Out of 20 students 18 play basketball and 9 play baseball.
So, some students play both the sports.
No. of students who play both sports = 18 + 9 - 20
= 7
p(student will play both) = 7/30
Probability that a student will play both is 7/30
30 divided by 3. Their are 3 sets of ten by 30 positives