![\bf \int [11\ ln\left( \sqrt[3]{x} \right)]dx\qquad \begin{cases} ln\left( \sqrt[3]{x} \right)\implies ln\left( x^{\frac{1}{3}} \right) \\ \quad \\ \frac{1}{3}ln(x) \end{cases}\qquad thus \\ \quad \\\\ \quad \\ \int [11\ ln\left( \sqrt[3]{x} \right)]dx\implies \int[11\cdot \frac{1}{3}ln(x)]dx\impliedby \textit{scalars to the left} \\ \quad \\ 11\cdot \frac{1}{3}\int[ln(x)]dx\implies \cfrac{11}{3}\int[ln(x)]dx](https://tex.z-dn.net/?f=%5Cbf%20%5Cint%20%5B11%5C%20ln%5Cleft%28%20%5Csqrt%5B3%5D%7Bx%7D%20%5Cright%29%5Ddx%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Aln%5Cleft%28%20%5Csqrt%5B3%5D%7Bx%7D%20%5Cright%29%5Cimplies%20ln%5Cleft%28%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Cright%29%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Cfrac%7B1%7D%7B3%7Dln%28x%29%0A%5Cend%7Bcases%7D%5Cqquad%20thus%0A%5C%5C%20%5Cquad%20%5C%5C%5C%5C%20%5Cquad%20%5C%5C%0A%5Cint%20%5B11%5C%20ln%5Cleft%28%20%5Csqrt%5B3%5D%7Bx%7D%20%5Cright%29%5Ddx%5Cimplies%20%5Cint%5B11%5Ccdot%20%5Cfrac%7B1%7D%7B3%7Dln%28x%29%5Ddx%5Cimpliedby%20%5Ctextit%7Bscalars%20to%20the%20left%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A11%5Ccdot%20%5Cfrac%7B1%7D%7B3%7D%5Cint%5Bln%28x%29%5Ddx%5Cimplies%20%5Ccfrac%7B11%7D%7B3%7D%5Cint%5Bln%28x%29%5Ddx)
and I'm pretty sure you know what that is
Using thereoms/postulates, we know that the 60° angle and the (5z - 85)° angle are congruent
so to first find z..



now that we know z, we can find x
simply replace the z in (5z - 85) with 29
and add the entire angle to x to equal 180
(supplementary angles)




Answer:
38 yards²
Step-by-step explanation:
Area of trapeziods= ½(a+b)×height
a and b are the parallel lengths of the trapezoid.
Area of trapeziod= ½ (5.6+13.4)×4= 38 yards²
Therefore, the correct option is B
If you liked this, please give a brainliest, thank you!
Answer:
88
Step-by-step explanation:
5GP= BP
2BNP= GNP
BP+BNP=333
GP+GNP=225
BNP= 333-BP
BNP= 333-5GP
GP= 225-GNP
GP= 225-2BNP
BNP=333-5(225-2BNP)
BNP=333-1125+10BNP
-9BNP=-792
BNP=88
Hope it helps :)
Mark Brainliest if possible.