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Inessa [10]
3 years ago
7

Triangle ABC has vertices A(5, 3) , B(3, 7) , and C(1, 4) . Triangle ABC is dilated, and the vertices of the image are A′(1.25, 

0.75) , B′(0.75, 1.75) , and C′(0.25, 1) . The center of dilation is the origin.
What is the scale factor of the dilation?

A.) 0.25

B.) 0.5

C.) 2

D.) 4
Mathematics
1 answer:
never [62]3 years ago
4 0
Hello,

To find the scale factor, we need to determine how the points are changing.

Point A is changing from (5, 3) to (1.25, 0.75). Therefore, we can write the following two equations using K as the scale factor.

5k = 1.25  or 3K = 0.75

Solving either equation will give you a scale factor of 0.25.

Good luck,
MrEQ

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Find the distance between the point (-3,5,8) and (8,12,2)
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Learn how to find the distance between two points by using the distance formula, which is an application of the Pythagorean theorem. We can rewrite the Pythagorean theorem as d=√((x_2-x_1)²+(y_2-y_1)²) to find the distance between any two points.
8 0
3 years ago
A student researcher compares the heights of men and women from the student body of a certain college in order to estimate the d
maria [59]

Answer:

(0.6613, 8.3387)

Step-by-step explanation:

Let the heights of men be the first population and the heights of women be the second population. Then

We have n_{1} = 15, \bar{x}_{1} = 69.4, s_{1} = 3.09 and

n_{2} = 7, \bar{x}_{2} = 64.9, s_{2} = 2.58. The pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(15-1)(3.09)^{2}+(7-1)(2.58)^{2}}{15+7-2} = 8.68

The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{15}+\frac{1}{7}}, i.e.,

(69.4-64.9)\pm t_{0.005}2.946\sqrt{\frac{1}{15}+\frac{1}{7}}

where t_{0.005} is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So  

4.5\pm(-2.845)(2.946)(0.458), i.e.,

(0.6613, 8.3387)

5 0
3 years ago
At which value in the domain does f(x)=0 ?
lina2011 [118]

f(x)=0

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f(x)=0 , we find all the x values where y =0

At x intercepts y is always 0

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x intercepts are the points where the graph crosses x axis

In the graph we can see that the graph crosses x axis at

-2.5 , -0.75 and 1

-2.5 , -0.75 and 1 are the domain where f(x)=0

5 0
3 years ago
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Aleksandr [31]

Answer:

the answer is 0.

Step-by-step explanation:

this is correct i just did the problem on khan

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Klio2033 [76]

Answer:

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Step-by-step explanation:

Rearranging the data from lowest to highest.

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The lower quartile would be 3 and 4

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