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3 years ago

6

What is a stock index?

2 answers:

stepladder [879]3 years ago

7 0

Is a measurement of the value of a section of the stock<span>market. It is computed from the prices of selected stocks (typically a weighted average). It is a tool used by investors and financial managers to describe the market, and to compare the return on specific investments. HOPE THIS HELPS</span>

mr_godi [17]3 years ago

3 0

The answer on Edgenuity is B

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Which is the equation of the line that passes through the point (-5, -2)

Lilit [14]

Answer:

F) y=3x+13

Step-by-step explanation:

y-y1=m(x-x1)

y-(-2)=3(x-(-5))

y+2=3(x+5)

y=3x+15-2

y=3x+13

5 0

3 years ago

Need help with my homework 2 problems

Solnce55 [7]

4(x+2) , 2(2x+4) , 8+4x , 1/2(8x+16) are all the same as 4x+ 8.

5 0

3 years ago

Change the following into the form f(x)=mx+b a. 8x-y=2 b.-3x+2y=9

kiruha [24]

Answer:

B

Step-by-step explanation:

I took the test

4 0

3 years ago

Solve the following linear equation for x x. 5 x − 2 + x = 9 + 3 x + 10 5x−2+x=9+3x+10

marta [7]

The answer is 6. Please mark BRAINLIEST!! :D

6 0

2 years ago

Surface Area of Cylinder=2πrh+2πr2

Alex

Find the surface area when r is 8 inches and h is 8 inches.

$\qquad$ A. 160π in²

$\qquad$ B. 154π in²

$\qquad$ C. 288π in²

$\qquad$ D. 256π in² ☑

We are given –

$\qquad$ ⇢Radius of cylinder , r = 8 inches

$\qquad$ ⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

$\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }$

Now, Substitute given values –

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8 \times 8 + 2\pi \times 8^2$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} =128 \pi + 128\pi$

$\purple{\bf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 256\pi \: in^2 }$

Henceforth,Option D is the correct answer.

8 0

2 years ago