Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
( 
) & ( 
)-
y - 
= 
( x - 
)
i.e. <em> y - 7= 
( x- 1)</em>
<em> y - 7 = 
( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.
It’s the vertical line on the graph
Answer:
(0,-1),(1,0),(2,1),(3,2)
Step-by-step explanation:
We are given that a relation
y=x+1y=x+1
We have to find the four points contained in the inverse
The given function is linear function
Therefore,
Domain of function=R
Range of function=R
x=y-1x=y−1
Now, replace x by y and y replace by x
y=x-1y=x−1
Now, substitute y=f^{-1}(x)=f
−1
(x)
f^{-1}(x)=x-1f
−1
(x)=x−1
It is linear function and defined for all real values.
Substitute x=0
f^{-1}(0)=-1f
−1
(0)=−1
Substitute x=1
f^{-1}(1)=1-1=0f
−1
(1)=1−1=0
f^{-1}(2)=2-1=1f
−1
(2)=2−1=1
f^{-1}(3)=3-1=2f
−1
(3)=3−1=2
Therefore, four points contained in the inverse (0,-1),(1,0),(2,1) and (3,2)
Factor x as it is a common factor;
x(8+3)
=11x
