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kow [346]
3 years ago
6

How do you waste time during this event?

SAT
2 answers:
Iteru [2.4K]3 years ago
4 0

Answer:

hi

Explanation:

uhhhhhhhhhhhhhhhhhhhhhhhhhhhhh idk

Talja [164]3 years ago
4 0
I just draw and watch Netflix tbh
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considering periodic trends, valence electrons in which of the following atoms experience the greatest effective nuclear charge
Anni [7]

The <em>effective nuclear charge</em> is the difference between the atomic number an element and the shielding constant. Hence, the atom which experiences the greatest nuclear charge is Sulphur, S.

<u>Calculating the greatest effective nuclear charge</u>, :

  • Z_{eff} = Z - S

  • Z = Atomic number ; S = shielding constant

<u>For Magnesium, Mg</u>:

Z = 12

S = 10

Z_{eff} = 12 - 10 = 2

<u>For Aluminium, Al</u>:

Z = 13

S = 10

Z_{eff} = 12 - 10 = 3

For Sulphur, , S:

Z = 16

S = 10

Z_{eff} = 16 - 10 = 6

Therefore, the atom whuch experience the greatest Z_{eff} is Sulphur.

Learn more :brainly.com/question/24978746

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A thumbnail sketch has proportional width and height.<br><br> A. True<br> B. False
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A

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If you can't provide proof of insurance to the FLHSMV, your driver license and license plate can be suspended for up to _____.
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Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca
antoniya [11.8K]

The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t} (1)

Where:

  • T_{s} - Final temperature, in degrees Celsius.
  • T_{o} - Initial temperature, in degrees Celsius.
  • t - Time, in minutes.
  • k - Cooling rate, in \frac{1}{min}.
  • T(t) - Current temperature, in degrees Celsius.

Please notice that substance reaches thermal equilibrium when T(t) = T_{s}, that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that T_{o} = 80\,^{\circ}C, t = 15\,min, T_{s} = 50\,^{\circ}C and T(15) = 60\,^{\circ}C, then the cooling rate of the substance is:

60 = 50 + (80 - 50)\cdot e^{-15\cdot k}

\frac{60-50}{80-50}= e^{-15\cdot k}

\frac{1}{3} = e^{-15\cdot k}

k = -\frac{1}{15}\cdot \ln \frac{1}{3}

k \approx 0.0732

The cooling rate of the substance is approximately 0.0732.

To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261

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