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elixir [45]
3 years ago
8

Convert 22.6 square centimeters to square inches (to the nearest hundredth). 3.50

Mathematics
2 answers:
kramer3 years ago
7 0
Im pretty sure the answer is <span>3.50. </span>
zysi [14]3 years ago
5 0
You need a conversion factor that is 1 square inch over 6.45 squeare centimeters . So your answer is 22.6cm^2 × 1 square inch over 6.54 square centimeters . which will be 3.50
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An eagle takes off from the top of a cliff that is 125 meters high and flies upward. After t seconds, the height at which the ea
bezimeni [28]

Answer:

The instantaneous velocity of the eagle at the given time is  7.5 m/s.

Step-by-step explanation:

Given;

height of the cliff, h = 125 m

the height at which the eagle is flying, h(t) = 125 + 1.25t²

The velocity of the eagle is given by;

v = dh/dt

v = 2.5t

The instantaneous velocity of the eagle at t = 3 seconds is given by;

v = 2.5(3)

v = 7.5 m/s

Theerefore, the instantaneous velocity of the eagle at t = 3 seconds is  7.5 m/s.

3 0
3 years ago
Solve the problem 12 – (2 × 3)
Elis [28]
PEMDAS
Parentheses - Exponents - Multiplication/Division - Addition/Subtraction
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3 0
3 years ago
Help pls i have 5 minss, no links
KonstantinChe [14]

Answer:

3/25

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Xe^(-x^2/128) absolute max and absolute min
adoni [48]
f(x)=xe^{-x^2/128}
\implies f'(x)=e^{-x^2/128}+x\left(-\dfrac{2x}{128}\right)e^{-x^2/128}=\left(1-\dfrac1{64}x^2\right)e^{-x^2/128}

Extrema can occur when the derivative is zero or undefined.

\left(1-\dfrac1{64}x^2\right)e^{-x^2/128}=0\implies 1-\dfrac1{64}x^2=0\implies x^2=64\implies x=\pm8

Maxima occur where the first derivative is zero and the second derivative is negative; minima where the second derivative is positive. You have

f''(x)=-\dfrac1{32}xe^{-x^2/128}+\left(1-\dfrac1{64}x^2\right)\left(-\dfrac{2x}{128}\right)e^{-x^2/128}=\left(-\dfrac3{64}x+\dfrac1{4096}x^3\right)e^{-x^2/128}

At the critical points, you get

f''(-8)=\dfrac1{4\sqrt e}>0
f''(8)=-\dfrac1{4\sqrt e}

So you have a minimum at \left(-8,-\dfrac8{\sqrt e}\right) and a maximum at \left(8,\dfrac8{\sqrt e}\right).

Meanwhile, as x\to\pm\infty, it's clear that f(x)\to0, so these extrema are absolute on the function's domain.
6 0
4 years ago
What is next number in pattern 7, 11, 2, 18, -7
Helga [31]

Answer:

the answer is -7+-25=-32

6 0
2 years ago
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