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elixir [45]
3 years ago
8

Convert 22.6 square centimeters to square inches (to the nearest hundredth). 3.50

Mathematics
2 answers:
kramer3 years ago
7 0
Im pretty sure the answer is <span>3.50. </span>
zysi [14]3 years ago
5 0
You need a conversion factor that is 1 square inch over 6.45 squeare centimeters . So your answer is 22.6cm^2 × 1 square inch over 6.54 square centimeters . which will be 3.50
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Can u proof it pls indeed help<br>ΑΔΒ = ΒΔΑ.​
Contact [7]

Answer:

ΑΔΒ = ΒΔΑ because Δ stands for the difference between two numbers and the difference between two numbers doesn't change when switched to the other side.

6 0
3 years ago
Which of the following statements correctly describes the items shown below?<br> Y=-6x+7
viva [34]

Answer:

where is the option??

Step-by-step explanation:

I dont see any options but I can say that -6x is the slope and +7 is the y-intercept

8 0
2 years ago
Which is an example of a high-risk investment?
rewona [7]

stock in a start-up company


4 0
3 years ago
Read 2 more answers
find the coordinates of the points D ( 4, -4 ) and E ( 5, -5 ) after the transformation ( x; y ) ( x + 3, y -5
postnew [5]

Answer:

second option

Step-by-step explanation:

Given the rule

(x, y ) → (x + 3, y - 5)

This means add 3 to the original x- coordinate and subtract 5 from the original y- coordinate, that is

D(4, - 4 ) → D'(4 + 3, - 4 - 5 ) → D'(7, - 9 )

E(5, - 5 ) → E'(5 + 3, - 5 - 5 ) → E'(8, - 10 )

7 0
2 years ago
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
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