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3 years ago

According to the Venn Diagram below and given that P(A) = .4 as well as

Mathematics

1 answer:

7nadin3 [17]3 years ago

7 0

Hello,

P(A)=0.4

P(B)=0.3

P(AUB)+P(A∩B)=P(A)+P(B)

P(AUB)=0.4+0.3-0.1=0.6

Answer C

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yulyashka [42]

(4, -2)

Step-by-step explanation:

For a reflection across the y-axis, you need to change the sign of the x to the opposite of what it was.

(x, y) to (-x, y)

If C has the coordinates of (-4, -2), to figure out the coordinates of C' after a reflection of the y-axis, we will change the sign of the x.

C' would be located at the coordinates (4, -2).

7 0

3 years ago

Based on data collected from its production processes, Crosstiles Inc. determines that the breaking strength of its most popular

alexandr1967 [171]

Answer:

16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.

Step-by-step explanation:

We are given that the breaking strength of its most popular porcelain tile is normally distributed with a mean of 400 pounds per square inch and a the standard deviation of 12.5 pounds per square inch.

Let X = the breaking strength of its most popular porcelain tile

SO, X ~ Normal( $\mu=400,\sigma^{2}=12.5^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean breaking strength of porcelain tile = 400 pounds per square inch

$\sigma$ = standard deviation = 12.5 pounds per square inch

Now, probability that the popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch is given by = P(X > 412.5)

P(X > 412.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{412.5-400}{12.5}$ ) = P(Z > 1) = 1 - P(Z $\leq$ 1)

= 1 - 0.84 = 0.16

Therefore, 16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.

7 0

3 years ago

PLEASE HELP ASAP!!! Explain, thank you-

Nat2105 [25]

Answer:

The answer to your question is: $\sqrt[4]{2^{3} } + 1$

Step-by-step explanation:

$\frac{1}{\sqrt[4]{2- 1}} x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1} = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}$

= $\sqrt[4]{2^{3} } + 1$

6 0

3 years ago

Solve this quadratic equation <img src="https://tex.z-dn.net/?f=3a%20%7B%7D%5E%7B2%7D%20-%204%20%2B%201" id="TexFormula1" tit

ivann1987 [24]

Answer:

1 and 1/3

Step-by-step explanation:

3a² -4a +1 = 0

3a²- 3a - a+ 1= 0

3a(a-1) - (a-1)= 0

(a-1)(3a -1)= 0

a-1= 0 ⇒ a= 1

3a - 1= 0 ⇒ 3a= 1 ⇒ a= 1/3

5 0

3 years ago

A man on the fifth floor of a building shouts down to a person on the street. If the angle of elevation from the street to the m

AleksandrR [38]

Answer: 57 ft

Step-by-step explanation: Because drawing it up, we can make a right angled triangle with the right angle between the height of the man in the building and the distance out from the building of the man in the street, and the 35 degrees between the line connecting the man in the street with the man in the building, and the line out from the building of the man in the street. Then, tan of the 35 degree angle is = to opposite (40ft)/adjacent (to solve for). By cross multiplication, the A or adjacent (dist out from the building) = 40/0.7 (0.7 = tan of 35 degrees) so the answer is 57 ft.

3 0

3 years ago

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