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2 years ago

According to the Venn Diagram below and given that P(A) = .4 as well as

Mathematics

1 answer:

7nadin3 [17]2 years ago

7 0

Hello,

P(A)=0.4

P(B)=0.3

P(AUB)+P(A∩B)=P(A)+P(B)

P(AUB)=0.4+0.3-0.1=0.6

Answer C

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A common practice of airline companies is to sell more tickets for a particular flight than there are seats on the plane, becau

Serga [27]

Answer:

0.0159

Step-by-step explanation:

Given that a common practice of airline companies is to sell more tickets for a particular flight than there are seats on the plane, because customers who buy tickets do not always show up for the flight.

Here if X is the no of persons that do not show up, then X is binomial as each trial is independent with p = 0.04 and n =150 (no of tickets sold)

The plane is overbooked if more than 150 show up

i.e. less than 2 do not show up

Hence the probability that the airline overbooked this flight

= $P(X$

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3 years ago

This is flipping a figure over the axis of symmrtry

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Answer:

Step-by-step explanation:

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3 years ago

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DENIUS [597]

9514 1404 393

Answer:

x = 7

Step-by-step explanation:

We can write a proportion relating the short segment to the full length:

(x+1)/18 = 4/(4+5)

x +1 = 8 . . . . . . multiply by 18 and simplify

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2 years ago

In the diagram, ABC=ECD. Which statement is true?

Ne4ueva [31]

If you showed me the diagram I could give you an answer.

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3 years ago

It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 122 feet. A transportat

madreJ [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

the null hypothesis is $H_o : \mu = 122$

the alternative hypothesis is $H_a : \mu \ne 122$

The test statistics is $t = - 1.761$

The p-value is $p = P(Z < t ) = 0.039119$

$p \ge 0.01$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 122$

The sample size is n= 38

The sample mean is $\= x = 116 \ feet$

The standard deviation is $\sigma = 21$

Generally the null hypothesis is $H_o : \mu = 122$

the alternative hypothesis is $H_a : \mu \ne 122$

Generally the test statistics is mathematically evaluated as

$t = \frac { \= x - \mu }{\frac{ \sigma }{ \sqrt{n} } }$

substituting values

$t = \frac { 116 - 122 }{\frac{ 21 }{ \sqrt{ 38} } }$

$t = - 1.761$

The p-value is mathematically represented as

$p = P(Z < t )$

From the z- table

$p = P(Z < t ) = 0.039119$

$p \ge 0.01$

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2 years ago