Answer:

Step-by-step explanation:
Given,
Principal ( P ) = $ 6000
Amount ( A ) = $ 14550
Time ( T ) = 10 years
Rate ( R ) = ?
<u>Finding </u><u>the </u><u>Interest</u>
The sum of principal and interest is called an amount.
From the definition,

plug the values
⇒
Swap the sides of the equation
⇒
Move 6000 to right hand side and change its sign
⇒
Subtract 6000 from 14550
⇒
Interest = $ 8550
<u>Finding </u><u>the </u><u>rate </u>

plug the values
⇒
Calculate
⇒
⇒
Hope I helped!
Best regards!!
Answer:
D. 
Step-by-step explanation:
There is a translation 1 point up along the y axis and a compression of 4.
Moving a function up (let's use <em>h</em> for the amount of points up) would change the function as so:

Meanwhile, the compression would modify x in this case. You can eliminate any answers (A. and B.) that have no modification to x, and eliminate C., as a fraction modification would actually widen the graph instead of compress it.
Hope this helps! :]
Using: A^2+b^2=c^2
A&b= (√10)^2=10
10+10=c^2
20=c^2
(take the square root of 20)
c=2√5
Your answer is D
Answer: 15.7 minutes
Step-by-step explanation:
Let x be the time in the beginning (in minutes).
Given: The track team is trying to reduce their time for a relay race.
First they reduce their time by 2.1 minutes.
Then they are able to reduce that time by 10
If their final time is 3.96 minutes, then
x-t1-t2= 3.6
x= 3.6+ t1+ t2
x= 3.6+ 2.1+ 10
x= 15.7
Hence, their beginning time was 15.7 minutes.
Answer:
Step-by-step explanation:
tan(79°) = US/TU = 9.1/TU
TU = 9.1/tan(79°) = 1.8 ft