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tatuchka [14]
3 years ago
7

Is the line x = 6-7t, y = 1+2t, z= -7t parallel to the plane 2x+y+z?

Mathematics
1 answer:
natita [175]3 years ago
3 0

In the formula of the distance between a point and a plane (not any plane but a plane parallel to the original one, equation [1] ), keeping <span>D=2</span>, and d as d itself, we get:

<span><span>D=<span><span>|a<span>x1</span>+b<span>y1</span>+c<span>z1</span>+d|</span><span>√<span><span>a2</span>+<span>b2</span>+<span>c2</span></span></span></span></span>
<span>2=<span><span><span>∣∣</span>1⋅0+2⋅0+<span>(−2)</span>⋅<span>(−<span>12</span>)</span>+d<span>∣∣</span></span><span>√<span>1+4+4</span></span></span></span>
<span><span>|d+1|</span>=2⋅3</span> => <span><span>|d+1|</span>=6</span>First solution:
<span>d+1=6</span> => <span>d=5</span>
<span>→x+2y−2z+5=0</span>Second solution:
<span>d+1=−6</span> => <span>d=−7</span>
<span>→x+2y−2z−7=<span>0</span></span></span>
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Among all pairs of numbers (x,y) such that 3x+y=15, find the pair for which the sum of squares, x^2+y^2, is minimum. Write your
Dvinal [7]

Answer:

Minimum value occurs at (x, y) = (-5,0)

Step-by-step explanation:

Given: 3x + y =15

Rewriting this equation to Slope - Intercept form, we get:

y = -3x + 15

Squaring both sides,

$ y^2 = (-3x + 15)^2 $

$ \implies y^2 = 9x^2 - 90x + 225 $

Substituting in $ x^2 + y^2,$ we get:

$ x^2 + 9x^2 - 90x + 225 $

= $ 10x^2 - 90x + 225 $

Comparing this equation with $ ax^2 + bx + c $ we get $ a =10 $ and $ b = - 90 $.

The minimum value occurs at the axis of symmetry given by $ x = \frac{-b}{2a} $.

Therefore, x = - $ \frac{-90}{2.10} $

$ \implies x = 5 $

If x = 5, y = -3(5) + 15 = 0

Thus, the point becomes (5,0) where it is minimum.

5 0
4 years ago
2 points
natima [27]

Answer:

4.9 feet

Step-by-step explanation:

First, we need to determine the height of the building using the following:

L^2 = H^2 + B^2

Where

H = Height of the building

L = Length of the first ladder = 20ft

B = Distance from the base of the building = 10ft

So, we have:

20^2 = H^2 + 10^2

400 = H^2 + 100

H^2 = 400 - 100

H^2 = 300

H = \sqrt{300

Next, is to determine the distance of the new ladder from the base of the building (B) using Pythagoras theorem using:

L_2^2 = H^2 + B_2^2

Where

L_2 = 18 --- Length of the second ladder

H = \sqrt{300 ----- Height of the building

So, we have:

18^2 = \sqrt{300}^2 + B_2^2

324 = 300 + B_2^2

B^2_2 = 324 - 300

B^2_2 = 24

Solving for B2, we have:

B_2 = \sqrt{24

B_2 = 4.9

8 0
3 years ago
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RideAnS [48]

Answer:

If your saying estimate this number in a decimal without calculators I think I might be able to help as illustrated below:

Step-by-step explanation:

2 5/6 shows that the whole number will be a 2. The 5/6 is a decimal below one as it is not one whole fraction. This means that we have to estimate the value of 5/6 and add that value to the number 2. 1/3 is a common fraction that is equal to about 0.33. This is because 0.33 + 0.33 + 0.33 is almost 1, which means 1/3 of one is indeed equal to 0.33.

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I would then say that the estimate of 2 5/6 is 2.83.

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